Question

我有一个在两个索引处都有值的数组，我想将两个索引的值填充到一个可能在不同数组中的索引中。

this.nodesObjResultSingular =  (2) [Array(6), Array(6)]

this.nodesObjResultSingular = [
[
    {sets: Array(1), size: 12},
    {sets: Array(1), size: 12},
    {sets: Array(1), size: 12},
    {sets: Array(2), size: 2},
    {sets: Array(2), size: 2},
    {sets: Array(2), size: 2}
],
[{sets: Array(1), size: 12},
{sets: Array(1), size: 12},
{sets: Array(1), size: 12},
{sets: Array(2), size: 2},
{sets: Array(2), size: 2},
{sets: Array(2), size: 2}]
];

如何获得以下信息？

finalVenn = // all the 12 values of this.nodesObjResultSingular.

Answer 1

使用传播运算符连接它们。喜欢：

finalVenn = [...this.nodesObjResultSingular[0], ...this.nodesObjResultSingular[1]]

或者也可以使用Array.concat()

finalVenn = this.nodesObjResultSingular[0].concat(this.nodesObjResultSingular[1])

如果要连接多个索引，请使用：

var multipleArr = [[1], [2, 3], [4, 5, 6 ]]
var res = [].concat.apply([], multipleArr)
console.log(res)

Answer 2

如果数组的数目未知，则可以将 reduce 与 concat 一起使用：

let data = [
[{sets: Array(1), size: 12},{sets: Array(1), size: 12},{sets: Array(1), size: 12},{sets: Array(2), size: 2},{sets: Array(2), size: 2},{sets: Array(2), size: 2}],
[{sets: Array(1), size: 12},{sets: Array(1), size: 12},{sets: Array(1),size: 12},{sets: Array(2), size: 2},{sets: Array(2), size: 2},{sets: Array(2), size: 2}]];

var merged = data.reduce((acc, arr) => acc.concat(arr), []);
console.log(merged);

如何在JavaScript中将所有数组值填充到单个索引

2 个答案: