Question

我使用Django将应用程序开发到博客问题是当我打开出版物的链接时例如，https：// //本地主机：8000 / article / 89 / 我想打开另一个小册子的链接，然后看一下 https：//本地主机：8000 / article / 89 / article / 80 / 每当您单击链接时，都会发生相同的情况请问有解决办法

view.py文章

def show_article(request, id):

post = get_object_or_404(articles, id=id)
add = comment_put.objects.all().filter(user_put = id).order_by('-id')
art = articles.objects.get(pk = id)
first = articles.objects.order_by('-id')[:1]
three = articles.objects.order_by('-id')[:4]

is_liked = False

if post.likes.filter(id=request.user.id).exists():
    is_liked = True

context = {
     'art': art,
     'add': add,
     'post': post,
     'first': first,
     'three': three,
     'is_liked': is_liked,
     'total_likes': post.total_likes(),


      }


return render(request, 'home/article.html', context)

urls.py

  url(r'article/(?P<id>\d+)/$', views.show_article, name='show_article'),

article.html

<!-- column -->
 {% for sd in solo1 %}
<div class="col-lg-3 col-md-4">

 <div class="card" style="width: 18rem;">
 <img class="card-img-top" src="{{sd.image.url}}" alt="Card image cap">
 <div class="card-body">
     <a class="" href="article/{{sd.id}}" style="color:#212529; text-decoration: none !important"><p class="card-text">{{sd.title}}</p></a>
  </div>
 </div>

</div>
<!--end column -->
{% endfor %}

Answer 1

只需从斜杠开始链接即可！ /

<a class="" href="/article/{{sd.id}}" style="color:#212529; text-decoration: none !important"><p class="card-text">{{sd.title}}</p></a>

当您的浏览器中有http://example.com/page/1/且链接类似于page / 2时，您将得到此结果http://example.com/page/1/page/2，而当链接为'/ page2'时，您将会得到http://example.com/page/2/

如何使用Django的Barre链接仅显示特定的网址

1 个答案: