Question

我有一个字符串：

[LVL 5] Steff_Kingston(ONLINE: 103)
[LVL 4] Oscar_Porsche(ONLINE: 733)
[LVL 3] Kenny_NewSide(ONLINE: 32)
[LVL 1] Juliette_Ortega(ONLINE: 290)Evgeniy_Kytyzov (phoenix tucson 
scottdale chandler brainburg saintrose mesa redrock events helpers ) 2018- 
12-12 23:51:54Esten_Middles (phoenix tucson scottdale chandler brainburg 
saintrose mesa redrock central events helpers ) 2018-12-12 
23:52:31Steff_Kingston

但是我只需要：

[LVL 5] Steff_Kingston(ONLINE: 103)
[LVL 4] Oscar_Porsche(ONLINE: 733)
[LVL 3] Kenny_NewSide(ONLINE: 32)
[LVL 1] Juliette_Ortega(ONLINE: 290)

可以是：

[LVL 3] Kenny_NewSide(ONLINE: 32)
[LVL 1] Juliette_Ortega(ONLINE: 290)Evgeniy_Kytyzov (phoenix tucson 
scottdale chandler brainburg saintrose mesa redrock events helpers ) 2018- 
12-12 23:51:54Esten_Middles (phoenix tucson scottdale chandler brainburg

我只需要

[LVL 3] Kenny_NewSide(ONLINE: 32)
[LVL 1] Juliette_Ortega(ONLINE: 290)

字符数可能会有所不同。我该怎么做？ PHP

Answer 1

以下是将preg_split与环视一起使用的一种选择：

$input = "[LVL 5] Steff_Kingston(ONLINE: 103) "; // and the rest of your input
$parts = preg_split("/(?<=Juliette_Ortega\(ONLINE: 290\))(?=Evgeniy_Kytyzov)/", $input);
print_r($parts[0]);

[LVL 5] Steff_Kingston(ONLINE: 103)
[LVL 4] Oscar_Porsche(ONLINE: 733)
[LVL 3] Kenny_NewSide(ONLINE: 32)
[LVL 1] Juliette_Ortega(ONLINE: 290)

正则表达式逻辑说，要在之前为Juliette_Ortega(ONLINE: 290)和跟随为Evgeniy_Kytyzov的任意点分割字符串。然后，我们仅保留拆分的第一部分，即您的预期输出。

Answer 2

您可以通过在(ONLINE...)部分上拆分字符串，捕获拆分后的字符串，然后删除拆分数组中的最后一项来完成此操作：

$input = '[LVL 5] Steff_Kingston(ONLINE: 103)
[LVL 4] Oscar_Porsche(ONLINE: 733)
[LVL 3] Kenny_NewSide(ONLINE: 32)
[LVL 1] Juliette_Ortega(ONLINE: 290)Evgeniy_Kytyzov (phoenix tucson 
scottdale chandler brainburg saintrose mesa redrock events helpers ) 2018- 
12-12 23:51:54Esten_Middles (phoenix tucson scottdale chandler brainburg 
saintrose mesa redrock central events helpers ) 2018-12-12 
23:52:31Steff_Kingston ';
$parts = preg_split('/(\(ONLINE:\s+\d+\))/', $input, -1, PREG_SPLIT_DELIM_CAPTURE);
array_pop($parts);
echo join('', $parts);

输出：

[LVL 5] Steff_Kingston(ONLINE: 103) 
[LVL 4] Oscar_Porsche(ONLINE: 733) 
[LVL 3] Kenny_NewSide(ONLINE: 32) 
[LVL 1] Juliette_Ortega(ONLINE: 290)

Demo on 3v4l.org

更新

假设您实际要做的是删除(ONLINE: nnn)和下一个[LVL n]之间的任何内容，则可以只使用preg_replace：

echo preg_replace('/(\(ONLINE:\s+\d+\)).*?(\[LVL|$)/s', "$1\n$2", $input);

Demo on 3v4l.org

需要修剪绳子

2 个答案: