我正在尝试在打字稿中为nvd3图表的array对象数组排序，但没有运气，对此表示感谢，
数据看起来像这样
[
{"k": "Name1", "val": [{"s": 33, "d": "sa"}, {"s": 1, "d": "as"}, {"s": 56, "d": "te"}]}
{"k": "Name2", "val": [{"s": 31, "d": "re"}, {"s": 4, "d": "sa"}, {"s": 1, "d": "ba"}]}
]
输出应为以下内容，
[
{"k": "Name1", "val": [{"s": 1, "d": "as"}, {"s": 33, "d": "sa"}, {"s": 56, "d": "te"}]}
{"k": "Name2", "val": [{"s": 1, "d": "ba"}, {"s": 4, "d": "sa"}, {"s": 31, "d": "re"}]}
]
我试图做这样的事没有运气，
arr=[
{"k": "Name1", "val": [{"s": 33, "d": "sa"}, {"s": 1, "d": "as"}, {"s": 56, "d": "te"}]}
{"k": "Name2", "val": [{"s": 31, "d": "re"}, {"s": 4, "d": "sa"}, {"s": 1, "d": "ba"}]}
]
arr.sort((a,b) => (a.s > b.s) ? 1 : ((b.s > a.s) ? -1 : 0));
对此表示任何帮助
答案 0 :(得分：0)
您要对数组中的“ val”键进行正确排序吗？这就是您要做的。
arr.map( (element) => element.val.sort(
(a,b) => (a.s > b.s) ? 1 : ((b.s > a.s) ? -1 : 0))
);
答案 1 :(得分：0)
您可以同时使用reduce和sort
const input = [
{"k": "Name1", "val": [{"s": 33, "d": "sa"}, {"s": 1, "d": "as"}, {"s": 56, "d": "te"}]},
{"k": "Name2", "val": [{"s": 31, "d": "re"}, {"s": 4, "d": "sa"}, {"s": 1, "d": "ba"}]}
];
const output = input.reduce( (prev, element) => {
const item = element;
Object.assign({}, item, {val: element.val.sort((a,b) => a.s- b.s)});
return prev.concat(item);
},[])
console.log({output});
答案 2 :(得分：0)
您应该使用forEach，因为它不会返回类似map和reduce的结果，从而有效地将数组重新放置在适当的位置。
const data = [
{"k": "Name1", "val": [{"s": 33, "d": "sa"}, {"s": 1, "d": "as"}, {"s": 56, "d": "te"}]},
{"k": "Name2", "val": [{"s": 31, "d": "re"}, {"s": 4, "d": "sa"}, {"s": 1, "d": "ba"}]}
]
data.forEach(obj => {
obj.val.sort((a, b) => a.s - b.s);
})
console.log(data)