我之前在这里问过类似的问题,但是我的代码已经改变了很多,我无法弄清楚。我确信这是我要传递给动作/减速器的问题。如果有人可以在这里解释我做错了什么,我将不胜感激。我真的很想得到它,只是很难受。
actions.js
import { ADD_TODO, REMOVE_TODO } from '../constants/action-types';
export const addTodo = (todo) => (
{
type: ADD_TODO,
payload: todo
}
);
export const removeTodo = (id) => (
{
type: REMOVE_TODO,
payload: id
}
)
reducers.js
import { ADD_TODO, REMOVE_TODO, ADD_OPTIONS } from '../constants/action-types';
import uuidv1 from 'uuid';
const initialState = {
todos: []
};
const rootReducer = (state = initialState, action) => {
switch (action.type) {
case ADD_TODO:
return {
...state,
todos: [...state.todos,
{
title: action.payload.inputValue,
id: uuidv1(),
createdAt: Date(),
priority: '',
deadline: '',
isClicked: false
}]
}
case REMOVE_TODO:
return {
...state,
todos: [...state.todos.filter(todo => todo.id !== action.payload)]
}
case ADD_OPTIONS:
return {
...state,
todos: [...state.todos,
{
isClicked: false
}]
}
default:
return state;
}
}
export default rootReducer;
TodoList.js
import React, { Component } from 'react';
import TodoItem from './TodoItem';
import { removeTodo } from '../actions';
import { connect } from 'react-redux';
const mapDispatchToProps = dispatch => {
return {
removeTodo: id => dispatch(removeTodo(id))
};
};
const mapStateToProps = state => {
return {todos: [...state.todos]};
};
class List extends Component {
render() {
const mappedTodos = this.props.todos.map((todo, index) => (
<TodoItem
title={todo.title}
key={index}
removeTodo={this.props.removeTodo}
/>
));
return (
mappedTodos
);
}
}
const TodoList = connect(mapStateToProps, mapDispatchToProps) (List)
export default TodoList;
TodoItem.js
import React, { Component } from 'react';
import uuid from 'uuid';
import '../../css/Todo.css';
class TodoItem extends Component {
render() {
const todoId = uuid();
return (
<div id={todoId}>
{this.props.title}
<button onClick={this.props.removeTodo}>X</button>
</div>
);
}
}
export default TodoItem;
答案 0 :(得分:1)
您需要将remove处理程序包装在一个表达式中,该表达式可以在“单击时间”求值,并使用闭包中的todo ID:
class TodoItem extends Component {
render() {
const todoId = uuid();
return (
<div id={todoId}>
{this.props.title}
<button onClick={this.props.removeTodo}>X</button>
</div>
);
}
}
应该是...
class TodoItem extends Component {
render() {
const todoId = uuid();
return (
<div id={todoId}>
{this.props.title}
<button onClick={() => this.props.removeTodo(todoId)}>X</button>
</div>
);
}
}
答案 1 :(得分:0)
就像@The Dembinski所说的一样,当我将TodoList组件更改为以下形式时,它可以工作:
import React, { Component } from 'react';
import TodoItem from './TodoItem';
import { removeTodo } from '../actions';
import { connect } from 'react-redux';
const mapDispatchToProps = dispatch => {
return {
removeTodo: id => dispatch(removeTodo(id))
};
};
const mapStateToProps = state => {
return {todos: [...state.todos]};
};
class List extends Component {
render() {
const mappedTodos = this.props.todos.map((todo, index) => (
<TodoItem
title={todo.title}
key={index}
removeTodo={() => this.props.removeTodo(todo.id)}
/>
));
return (
mappedTodos
);
}
}
const TodoList = connect(mapStateToProps, mapDispatchToProps) (List)
export default TodoList;
在此处更改地图上的removeTodo道具DID已解决该问题,现在可以正确删除。但是,如果有人可以通过进一步的讨论,或者只是通过向我指出我应该研究的正确方向来帮助我更好地理解这一点。将不胜感激。我没有答案,我正在学习。