Question

所有内容都可以编译，但是当我运行程序时，它似乎完全跳过了player1函数，直接进入了printBoard函数，当我在循环之前要求player1中需要的变量时，它会将它们带入并且仍然跳过循环。我以前有另一个布尔函数，可以正常工作

#include<iostream> 

using namespace std;

char board[9] = { 1, 2, 3, 4, 5, 6, 7, 8, 9 };
void printBoard();
bool player1(char);
int main()
{
    char m;
    char x;
    char o;

    cout << "Welcome to Tic- Tac- Toe!" << endl;
    cout << "Choose your mode: " << endl;
    cout << "1: Player vs Player" << endl;

    cin >> userCommand;

    if (userCommand == 1) {
        cout << "Player vs Player" << endl;
        cout << "Player 1 will use 'X'" << endl;
        cout << "Player 2 will use 'O'" << endl;

        printBoard();

        while (!player1) {
            cout << "Player 1 please enter space: ";
            cin >> m;
        }

        printBoard();
    }
    else {
        cout << "Player vs AI";
    }

    return 0;
}

void printBoard()
{
    cout << board[0] << "|" << board[1] << "|" << board[2] << endl;
    cout << "-"
         << " "
         << "-"
         << " "
         << "-" << endl;
    cout << board[3] << "|" << board[4] << "|" << board[5] << endl;
    cout << "-"
         << " "
         << "-"
         << " "
         << "-" << endl;
    cout << board[6] << "|" << board[7] << "|" << board[9] << endl;
}

bool player1(char m)
{
    if (board[m] == m) {
        board[m] = 'x';
        return true;
    }
    else {
        return false;
    }
}

Answer 1

您不是在调用player1，而是在检查它（该功能）是否存在。您需要传递参数...

因此它将是：

while(!player1(m))

（您仍然可以编译，因为按名称引用函数是有效的构造-将其视为指向函数本身的指针-并自动将其转换为bool，其中null转换为false，并将非null转换为true。）

程序不调用一个功能，而是调用其他功能

1 个答案: