Question

我有两个对象数组。在第二个数组中，您可以从第一个数组中分配一个ID。如果第一个数组的ID在array2中未关联，如何过滤第一个数组以仅显示结果？我已经尝试过在lodash中过滤器的嵌套过滤器和find过滤器的嵌套过滤器，但是它不起作用。

这是我尝试过的：

array1.filter（item => item.id === find（array2，{associateID：item.id}）[0] .associatedID）在过滤器内部进行查找的第二次迭代。我尝试了类似的过滤器方法而不是查找，但是那也不起作用。如在父过滤器参数中提供的那样，在find函数中使用item.id是否存在问题？还是没有？

帮助？

const array1 = [{
  "id": "1",
  "name": "Test 1"
},
{
  "id": "2",
  "name": "Test 2",
}
{
  "id": "3",
  "name": "Test 3",
}
]

const array2 = [{
  "id": "12",
  "name": "Test 1",
  "associatedID": "1"
},
{
  "id": "22",
  "name": "Test 2",
  "associatedID": "2"
}
{
  "id": "32",
  "name": "Test 3",
}
]

Answer 1

效果不佳的方法是

array1.filter(elm1 => {
  return array2.find(elm2 => elm2.associatedID === elm1).length === 1
})

如果您的数组很大，则可以根据ID和关联的ID对两个数组进行排序，并对两个数组运行一个for循环以某种方式返回结果

Answer 2

使用lodash的_.differenceWith()从array获取associatedID中没有array2的所有项目：

const array1 =[{"id":"1","name":"Test 1"},{"id":"2","name":"Test 2"},{"id":"3","name":"Test 3"}]

const array2 = [{"id":"12","name":"Test 1","associatedID":"1"},{"id":"22","name":"Test 2","associatedID":"2"},{"id":"32","name":"Test 3"}]

const result = _.differenceWith(array1, array2, 
  ({ id }, { associatedID }) => id === associatedID
);

console.log(result);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

Answer 3

只需使用from datetime import timedelta as td import datetime as da #flex = input("Enter your flex amount in HHMM:") flex = "0134" now = da.datetime.now() user_hours = int(flex[:2]) user_minute = int(flex[2:5]) delay = td(hours=user_hours, minutes=user_minute) balance = da.datetime.now()+delay print("Lunch: " +str(lunch)) print("Time when balance at 00:00 : " +str(balance)) print("Now: " +str(now))和Array.filter从Array.some中获取与array1不相关的项目：

array2

使用lodash也可以通过_.differenceWith完成此操作：

const array1 = [{ "id": "1", "name": "Test 1" }, { "id": "2", "name": "Test 2", }, { "id": "3", "name": "Test 3", } ]
const array2 = [{ "id": "12", "name": "Test 1", "associatedID": "1" }, { "id": "22", "name": "Test 2", "associatedID": "2" }, { "id": "32", "name": "Test 3", } ]

const result = array1.filter(x => !array2.some(y => y.associatedID == x.id))
console.log(result)

const array1 = [{ "id": "1", "name": "Test 1" }, { "id": "2", "name": "Test 2", }, { "id": "3", "name": "Test 3", } ]
const array2 = [{ "id": "12", "name": "Test 1", "associatedID": "1" }, { "id": "22", "name": "Test 2", "associatedID": "2" }, { "id": "32", "name": "Test 3", } ]

const result = _.differenceWith(array1, array2, (x,y) => x.id === y.associatedID)
console.log(result)

Lodash过滤/ Javascript中两个对象数组的交集

3 个答案: