#include <stdio.h>
#include <malloc.h>
struct el {
int info;
struct el* next;
};
struct el* create_el(struct el* Li)
{
int num;
printf("\n\nInsert number:\n\n");
scanf("%d", &num);
Li = (struct el*)malloc(sizeof(struct el));
if (Li != NULL) {
Li->info = num;
Li->next = NULL;
}
return (Li);
}
struct el* push(struct el* L, struct el* e)
{ //inserts the elements from the head of the list
if (L == NULL)
return (e);
else {
e->next = L;
L = e;
return (L);
}
}
void visualize(struct el* primo)
{
printf("\n\nList-->");
while (primo->next != NULL) {
printf("%d", primo->info);
printf("-->");
primo = primo->next;
}
if (primo->next == NULL)
printf("%d-->NULL", primo->info);
}
struct el* cancel(struct el** P, int val)
{ //delete element
struct el* prec = NULL;
struct el* curr = (*P);
if (P == NULL) //case empty list
return NULL;
else if (prec == NULL) {
if (curr->info == val) { //case 2 : if the element is the head
(*P)->next = curr->next;
free(curr);
curr = NULL;
}
}
else {
while ((curr != NULL) && (curr->info != val)) {
prec = curr;
curr = curr->next;
}
if (curr->next == NULL && curr->info == val) { // case 3: the elemnt is the last one
prec->next = NULL;
free(curr);
curr = NULL;
return (prec);
}
else {
if (curr->info == val) { //other cases
prec->next = curr->next;
free(curr);
curr = NULL;
return (prec);
}
}
}
}
int main()
{
struct el* head = NULL;
struct el* element;
struct el* list = NULL;
int i, n;
int elem;
printf("Insert the number of elements for the list:\n\n");
scanf("%d", &n);
for (i = 0; i <= n; i++) {
element = create_el(head);
if (element != NULL) {
list = push(list, element);
}
}
visualize(list);
printf("\n\nInsert the element that you want to cancel:");
elem = scanf("%d", &elem);
cancel(&list, elem);
visualize(list);
}
我想要做的就是从列表器中删除一个元素,但是在所有过程之后,列表将被打印而没有任何修改。
任何人都可以看到函数cancel中的错误吗(该函数旨在通过包含元素的任何可能位置来删除它)?
答案 0 :(得分:0)
在您的函数cancel
中,P
绝对不是NULL
(假设操作系统最初为其分配了地址)。
prec
是NULL
,执行进入if
循环之前。
因此,执行将执行该行
if(curr->info==val)
现在,如果您提供的值val
与curr->info
不匹配,则执行将退出该函数,而不会删除任何节点。