我正在尝试迭代连接一个字符串以使用“ for”循环构建url参数,但是我认为我遇到了范围界定问题。
The output should be: url_param = "&query_param=hello&query_param=world"
array_of_objects = [{'id':'hello'},{'id':'world'}]
{% set url_param = "" %}
{% set array_of_ids = array_of_objects|map(attribute='id')|list%} // correctly returns [1,2]
{% for id in array_of_ids %}
{% set param = '&query_param='~id %}
{% set url_param = url_param~param %}
{% endfor %}
//url_param is still an empty string
我也尝试了namespace(),但无济于事:
{% set ns = namespace() %}
{% set ns.output = '' %}
{% set array_of_ids = array_of_objects|map(attribute='id')|list%} // correctly returns [1,2]
{% for id in array_of_ids %}
{% set param = '&industries='~id%}
{% set ns.output = ns.output~param %}
{% endfor %}
//ns.output returns namespace
答案 0 :(得分:6)
这确实是一个范围问题。处理此问题的一种“ hacky”方式是使用一个列表,如下所示:
{% set array_of_objects = [{'id':'hello'},{'id':'world'}] %}
{% set array_of_ids = array_of_objects|map(attribute='id')|list%}
{{ array_of_ids|pprint }} {# output: ['hello', 'world'] #}
{% set ids = [] %} {# Temporary list #}
{% for id in array_of_ids %}
{% set param = '&query_param='~id %}
{% set url_param = url_param~param %}
{{ ids.append(url_param) }}
{% endfor %}
{{ ids|pprint }} {# output: [u'&query_param=hello', u'&query_param=world'] #}
{{ ids|join|pprint }} {# output: "&query_param=hello&query_param=world" #}
以上内容为您提供了所需的内容,但是对于此特定示例,我将研究如何使用jinja's join filter。它更具声明性,而且不那么骇人听闻。
{% set array_of_objects = [{'id':'hello'},{'id':'world'}] %}
{# set to a variable #}
{% set query_string = "&query_param=" ~ array_of_objects|join("&query_param=", attribute="id") %}
{{ query_string|pprint }}
{# output: u'&query_param=hello&query_param=world' #}
{# or just use it inline #}
{{ "&query_param=" ~ array_of_objects|join("&query_param=", attribute="id") }}