如何读取存储在二进制文件中的数组或变量,并在程序中将其打印出来?

时间:2018-12-12 01:03:11

标签: c file io binary

我很难从另一个c程序编写的文件中获取变量/元素的值,以存储到正在运行的c程序的变量/元素中。 将变量“ i”读入程序(这是一个已经确定并存储在文件“ inventory.txt”中的整数)时,我总是遇到分段错误。 “ i”表示要打印的数组的元素数量(大小)。这是损坏的代码):。

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int l, k;
    int *pn, *arraysize, *q;
    float *p;
    FILE *fp = fopen( "inventory.txt", "r+b" ); //declarations and I open up the binary file "inventory.txt"

    if ( fp == NULL )
    {                           //check file
        printf( "nah" );
        exit( EXIT_FAILURE );
    }

    *arraysize = fread( &arraysize, sizeof( int ), 1, fp );     //set arraysize in this program equal to i in the binary file inventory.txt?????? Here is where I get segmentation fault

    printf( "marker1" );        //place marker, I am not getting to this point when running the program

    for ( l = 0; l < *arraysize; l++ )
    {
        q[l] = fread( &q[l], sizeof( int ), arraysize, fp );    //set array elements ("arraysize" of them) pn, q, and p to the array elements of the same name in binary file inventory.txt
        p[l] = fread( &p[l], sizeof( int ), arraysize, fp );
        pn[l] = fread( &pn[l], sizeof( int ), arraysize, fp );
    }

    printf( "Below are the items in your inventory.\nPart#\tQuantity\tPrice\n" );       //print out the values
    for ( l = 0; l < *arraysize; l++ )
    {
        printf( "%5d\t", pn[l] );
        printf( "%8d\t", q[l] );
        printf( "%9.2f\n", p[l] );
    }
    return 0;
}

2 个答案:

答案 0 :(得分:0)

这是您的一些代码:

int *arraysize;
*arraysize=fread(&arraysize,sizeof(int),1,fp);

您将arraysize声明为int *(一个指针),但是随后您尝试将一个int读入其中。这是没有道理的。然后,您尝试取消对它的引用以存储返回值,该返回值将崩溃,因为它不是有效的指针。

您可能想要

int arraysize;
if (fread(&arraysize, sizeof(int), 1, fp) != 1) {
    fprintf(stderr, "error reading file\n");
    exit(1); }

arraysize声明为一个简单的int(不是指针)并读入其中。

您的其他fread呼叫也有类似的问题。

答案 1 :(得分:0)

您的指针有点错误,该代码从未分配任何内存来读取值,并且fread()返回读取的项数,该代码(由于某种原因)覆盖了以此方式读取的值结果。

这里是补丁版本,但是您不包含任何测试数据,因此未经测试。

#include <stdio.h>
#include <stdlib.h>

int main(  )
{
    int    l;
    int   *pn;
    int   *q;
    float *p;
    int    arraysize;

    FILE *fp = fopen( "inventory.txt", "r+b" ); //declarations and I open up the binary file "inventory.txt"

    if ( fp == NULL )
    {                           //check file
        printf( "nah" );
        exit( EXIT_FAILURE );
    }

    fread( &arraysize, sizeof( int ), 1, fp );     //set arraysize in this program equal to i in the binary file inventory.txt?????? Here is where I get segmentation fault

    printf( "marker1" );        //place marker, I am not getting to this point when running the program


    // Allocate some memory to hold the data (Yes! With cast on malloc())
    q  = (int *)malloc(arraysize * sizeof( int ));  // TODO - check malloc() OK
    pn = (int *)malloc(arraysize * sizeof( int ));  // TODO - check malloc() OK
    p  = (float *)malloc(arraysize * sizeof( float ));  // TODO - check malloc() OK

    // read each entire block in a single operation
    fread( q, sizeof( int ), arraysize, fp );    //set array elements ("arraysize" of them) pn, q, and p to the array elements of the same name in binary file inventory.txt
    fread( p, sizeof( float ), arraysize, fp );
    fread( pn, sizeof( int ), arraysize, fp );


    printf( "Below are the items in your inventory.\nPart#\tQuantity\tPrice\n" );       //print out the values
    for ( l = 0; l < arraysize; l++ )
    {
        printf( "%5d\t", pn[l] );
        printf( "%8d\t", q[l] );
        printf( "%9.2f\n", p[l] );
    }
    return 0;
}