因此,我花了很多时间来编写此查询,然后发现很难的方法是返回数组而不是activerecord关系。 DOH。这不会有问题,但是我需要在这些结果上使用Ransack,这需要关联。
因此,基本上,我需要使用.joins()和.select()语法将其转换为Rails,但是我尝试过的所有错误均已解决。我想我可能需要深入研究AREL?
或者,如果可以轻松地将其转换为具有最小性能问题并保留我的别名列的activerecord关系,那么它也可以工作!
对此有任何帮助或建议!
find_by_sql("
SELECT
subq.*,
renewal_date,
days_until_due,
renewal_stage_sort,
(
CASE
WHEN renewal_stage_sort IS NOT NULL THEN
CASE
WHEN days_until_due > 42 AND renewal_stage_sort >= 1 THEN TRUE
WHEN days_until_due > 28 AND days_until_due < 43 AND renewal_stage_sort >= 2 THEN TRUE
WHEN days_until_due > 13 AND days_until_due < 29 AND renewal_stage_sort >= 3 THEN TRUE
WHEN days_until_due > -1 AND days_until_due < 14 AND renewal_stage_sort >= 4 THEN TRUE
WHEN days_until_due < 0 AND renewal_stage_sort >= 5 THEN TRUE
ELSE FALSE
END
ELSE FALSE
END
)
AS on_target
FROM (
SELECT DISTINCT ON (renewals.id) renewals.*,
CASE
WHEN renewal_types.name = 'IEP-504' THEN patients.iep_renewal_date
WHEN renewal_types.name = 'RR' THEN patients.rr_date
ELSE NULL
END
AS renewal_date,
( CASE
WHEN renewal_types.name = 'IEP-504' THEN patients.iep_renewal_date::date
WHEN renewal_types.name = 'RR' THEN patients.rr_date::date
ELSE NULL
END
- current_date)
AS days_until_due,
renewal_stages.sort_order AS renewal_stage_sort
FROM renewals
INNER JOIN renewal_types ON renewal_types.id = renewals.renewal_type_id
LEFT JOIN renewal_stages ON renewal_stages.id = renewals.renewal_stage_id
INNER JOIN patients ON patients.id = renewals.patient_id AND patients.deleted_at IS NULL
WHERE renewals.deleted_at IS NULL
) subq
")
答案 0 :(得分:0)
实际上并不能完成全部工作,但这只是一个开始...
礼物:
RenewalStages.sortOrder.select(
[
Subq.arel_table[Arel.star], :renewal_date, :days_until_due, :renewal_stage_sort, Arel::Nodes::Group.new(
Arel.sql(
'CASE WHEN renewal_stage_sort IS NOT NULL THEN CASE WHEN days_until_due > 42 AND renewal_stage_sort >= 1 THEN TRUE WHEN days_until_due > 28 AND days_until_due < 43 AND renewal_stage_sort >= 2 THEN TRUE WHEN days_until_due > 13 AND days_until_due < 29 AND renewal_stage_sort >= 3 THEN TRUE WHEN days_until_due > -1 AND days_until_due < 14 AND renewal_stage_sort >= 4 THEN TRUE WHEN days_until_due < 0 AND renewal_stage_sort >= 5 THEN TRUE ELSE FALSE END ELSE FALSE END'
)
).as('on_target')
]
).where(Renewal.arel_table[:deleted_at].eq(nil))
是的,显然需要Arel表
答案 1 :(得分:0)
一个通用的解决方案是使用.from(subquery_sql)来完成最少的工作。然后,您可以从子查询中提取联接等,然后逐段提取到.joins中。
User.
from("(select distinct * from users where id > 0) users ").
select("users.*, false as mystatus").
first.
mystatus
由于您需要ActiveRecord :: Relation,因此需要使用正确的方法https://api.rubyonrails.org/classes/ActiveRecord/QueryMethods.html如果直接使用Arel来构建查询,由于它不了解模型,因此无法解决问题,只知道关于表,选择,分组,查询参数等,这是低级的。
您没有发布架构,因此我尚未验证以下代码是否有效,但是类似这样
fromsql = <<-SQL
(
SELECT DISTINCT ON (renewals.id) renewals.*,
CASE
WHEN renewal_types.name = 'IEP-504' THEN patients.iep_renewal_date
WHEN renewal_types.name = 'RR' THEN patients.rr_date
ELSE NULL
END
AS renewal_date,
( CASE
WHEN renewal_types.name = 'IEP-504' THEN patients.iep_renewal_date::date
WHEN renewal_types.name = 'RR' THEN patients.rr_date::date
ELSE NULL
END
- current_date)
AS days_until_due,
renewal_stages.sort_order AS renewal_stage_sort
FROM renewals
INNER JOIN renewal_types ON renewal_types.id = renewals.renewal_type_id
LEFT JOIN renewal_stages ON renewal_stages.id = renewals.renewal_stage_id
INNER JOIN patients ON patients.id = renewals.patient_id AND patients.deleted_at IS NULL
WHERE renewals.deleted_at IS NULL
) renewals
SQL
select_sql = <<-SQL
renewals.*,
renewal_date,
days_until_due,
renewal_stage_sort,
(
CASE
WHEN renewal_stage_sort IS NOT NULL THEN
CASE
WHEN days_until_due > 42 AND renewal_stage_sort >= 1 THEN TRUE
WHEN days_until_due > 28 AND days_until_due < 43 AND renewal_stage_sort >= 2 THEN TRUE
WHEN days_until_due > 13 AND days_until_due < 29 AND renewal_stage_sort >= 3 THEN TRUE
WHEN days_until_due > -1 AND days_until_due < 14 AND renewal_stage_sort >= 4 THEN TRUE
WHEN days_until_due < 0 AND renewal_stage_sort >= 5 THEN TRUE
ELSE FALSE
END
ELSE FALSE
END
)
AS on_target
SQL
Referal.from(fromsql).select(select_sql).to_sql