Question

我正在使用preg_match检查字符串中是否包含特定单词：

$string = 'This string contains a few words that are in an array!';
$arr = ['string', 'few', 'words'];

if(preg_match('['.implode('|', $arr).']', $string)){
    //do something if there is at least one word from the array inside that string
}

这工作得很好，但是如果至少有一个单词，它将返回true；如果该字符串中的数组中至少有两个单词，则我需要它返回true。

可以一步完成吗？如果没有，我应该从这里走哪条路来获得那个结果？

谢谢！：D

Answer 1

您可以为此使用preg_match_all

$string = 'This string contains a few words that are in an array!';
$arr = ['string', 'few', 'words'];
$count = preg_match_all('['.implode('|', $arr).']', $string); // Returns 3

Answer 2

如果您的要求是知道字符串中至少有 2 个必需的单词，那么您需要小心。如果您在字符串中有2个相同的单词，那么仅使用preg_match_all来搜索出现次数就很容易得到误报。

这将报告3，即所有3个单词都出现在大海捞针中

$string = 'This string contains a string and a few other words!';
$finds = ['string', 'few', 'words'];
$findCount = 0;

foreach ($finds as $find) {
    if ( strpos($string, $find) !== false ) $findCount++;
}
echo $findCount;

如果使用此字符串，它将报告2

$string = 'This string contains a string and a other words!';

最重要的是，如果您使用的字符串两次包含单词string，但不包含2个必需单词，则仅报告一个。

$string = 'This string contains a string and other stuff!';

Answer 3

如果您不希望完全匹配，则所选答案很好。如果要匹配完全匹配的单词，则需要使用单词边界\b。

这里是示例：

$arr = ['string', 'few', 'words'];

preg_match_all('#\b('.implode('|', $arr).')\b#', $string, $wordsFound);

$wordsFound = array_unique($wordsFound[0]);

if(count($wordsFound) >= 2){
    echo "Matched";
}else{
    echo "Not matched";
}


Input: $string = 'This string contains a few words that are in an array!';
Output: Matched (3 founds)

Input: $string = 'This string222 contains a few words that are in an array!';
Output: Matched (2 founds)

Input: $string = 'This string222 contains a few23 words that are in an array!';
Output: Not Matched (1 found)

Input: $string = 'This string contains a string words that are in an array!';
Output: Matched (2 founds)

Input: $string = 'This string contains a string string that are in an array!';
Output: Not Matched (1 found)

PHP检查字符串中是否至少包含两个特定的单词

3 个答案: