Question

我列出了一个元组列表（每个元组代表一个2D点），然后我想使用pyplot对其进行绘制。所以我的问题是，我无法通过切片列表来仅获得x个协调员。这是我正在使用的代码

points = [(1,2), (3,4), (5,6)]
plt.plot(points[:][0], points[:][1], 'o')

如果我想打印

in:  print(points[:][0])
out: (1, 2)

您是否知道如何获取第一个元组元素的列表？

Answer 1

@ForceBru的解决方案

select t.*
from (select t.*,
             sum(orders) over (order by orders desc range between unbounded preceding and current row) as running_orders,
             sum(orders) over (partition by orders) as all_with_this_order,
             sum(orders) over () as total_orders
      from t
     ) t
where (running_orders - all_with_this_order) < 0.75 * total_orders;

或更简单的方法（x，y现在是元组）

points = [(1,2), (3,4), (5,6)]
x = [p[0] for p in points]
y = [p[1] for p in points]

Answer 2

您需要做的就是理解列表，如下所示：

points = [(1,2), (3,4), (5,6)]
x_coordinats = [x[0] for x in points]
y_coordinats = [y[0] for y in points]

从元组列表中切片

2 个答案: