Question

我正在为驾校创建软件，但仅限于我可以使用哪些插件。我还必须为数据库使用文本文件，而不是能够使用SQL等。我似乎无法弄清楚下一阶段。这是场景：

每位教师都有唯一的登录名，他们可以选择将课程预订到日历/时间表上，也可以只查看它。问题是我不确定如何在不创建大量文本文件的情况下存储数据，因为最初我的想法是每位讲师都可以查看自己的个人日历/时间表（通过其唯一的登录信息链接在一起）但是，由于日历的工作原理，每周需要使用自己的文本文件，然后将文本文件的数量乘以教师总数。日历和时间表的代码是正确的（虽然工作并不完美，但是主要原理仍然存在）：

import sys
import re
from tkinter import *
import tkinter.messagebox as box
import tkinter.font as Font
import time
import calendar
#from tkinter import font
from tkinter import ttk
def Calendar():

    def mainTimetable():
        #root1 = Tk()

        #frame = Frame(root1)

        days = ["","Mon","Tue","Wed","Thur","Fri","Sat","Sun"]
        hours = ["","08:00","09:00","10:00","11:00","12:00","13:00","14:00","15:00",
                 "16:00","17:00","18:00"]

        class WrappedButtons:
            def __init__(self, master, **kwargs):
                self.button = Button(master,font=('Courier'),fg='#333333',bg='#CCCCCC', **kwargs)
                self.name = ''

            def nameToggle(self):
                if not self.name:
                    self.name = nameEntry.get()
                else:
                    self.name = ''
                self.button.config(text=self.name)

        def subTimetable():
            global nameEntry
            popup = Toplevel()
            #popup.title('Timetable')
            for x in range(12):
                Label(popup,font=('Courier'),fg='#333333',bg='#CCCCCC', text=hours[x]).grid(row=x,column=0)
            for x in range(8):
                Label(popup,font=('Courier'),fg='#333333',bg='#CCCCCC',text=days[x]).grid(row=0,column=x)
                if x < 7: # this avoids an extra column of buttons
                    for y in range(11):
                        temp = WrappedButtons(popup,width=20)
                        temp.button.config(command=temp.nameToggle)
                        temp.button.grid(row=y+1,column=x+1)
            Label(popup,text = "Enter the name of pupil and click the slot you wish to fill/remove: ")\
                .grid(row=13,column=0,columnspan=4)

            nameEntry = Entry(popup,width=40)
            nameEntry.grid(row=13,column=4,columnspan=2)


            backButton = Button(popup,font=('Courier'),fg='#333333',bg='#CCCCCC',text='Back',command= popup.destroy)#lambda: [f() for f in[popup.destroy,ownermenu]]).grid(row=13,column=6) # Add functionality to return to user page
            submitButton = Button(popup,text='Submit Data').grid(row=13,column=7)

            menubar = Menu(popup)
            filemenu = Menu(menubar,tearoff=0)
            filemenu.add_command(label='Home',command=lambda:[f() for f in [popup.destroy,home1]])
            filemenu.add_separator()
            filemenu.add_command(label='Exit',command=popup.destroy)
            menubar.add_cascade(label='Page',menu=filemenu)
            popup.config(menu=menubar)

            popup.configure(bg='#333333')

            #popup.overrideredirect(True)
            #popup.geometry("{0}x{1}+0+0".format(popup.winfo_screenwidth(), popup.winfo_screenheight()))

        subTimetable()
        #root.mainloop()


    root = Tk()
    root.title('Calendar')
    root.configure(bg='#333333')
    permanentFrame,newFrame = Frame(root), Frame(root)
    permanentFrame.pack(side='top')
    newFrame.pack(side='top')

    months = {1: 31, 2: 28, 3: 31, 4: 30, 5: 31, 6: 30, 7: 31, 8: 31, 9: 30, 10: 31, 11: 30, 12: 31}

    lbMonths = Label(permanentFrame,text='Months: ',fg='#333333',bg='#CCCCCC')
    lbMonths.pack()
    dropMonths = ttk.Combobox(permanentFrame, values=list(months.keys()))
    dropMonths.pack()


    class ButtonsWrap:
        def __init__(self,master,month,day, **kwargs):
            self.button = Button(master,**kwargs)
            self.monthInd = month-1
            self.dayInd = day-1
            self.toplevel = False
            self.thing = None

        def popClose(self):
            self.thing.destroy()
            self.toplevel = False
            self.thing = None

        def popup(self):
            if not self.toplevel:
                self.thing = Toplevel()
                self.toplevel = True
                #Label(self.thing, command=mainTimetable).pack()
                self.popClose
                mainTimetable()
                self.thing.protocol("WM_DELETE_WINDOW",self.popClose) #Add back in when 'back' functionality is complete



    buttons = []

    def makeCalendar(blank):
        curMonth = int(dropMonths.get())

        for i in buttons:
            if i.thing:
                i.thing.destroy()
        for i in newFrame.slaves():
            i.destroy()

        rows = [Frame(newFrame) for i in range(5)]
        [i.pack() for i in rows]

        curDay = 1

        for i in range(35):
            if len(rows[0].slaves()) == 7:
                rows.pop(0)
            temp = ButtonsWrap(rows[0], curMonth,curDay,text='',height=1,width=2)
            temp.button.pack(side='left')
            buttons.append(temp)
            if curDay <= months[curMonth]:
                temp.button.config(text=curDay,command=temp.popup)
                curDay += 1

    dropMonths.bind('<<ComboboxSelected>>', makeCalendar)
    menubar = Menu(root)
    filemenu = Menu(menubar,tearoff=0)
    filemenu.add_command(label='Home',command=lambda:[f() for f in [root.destroy,home1]])
    filemenu.add_separator()
    filemenu.add_command(label='Exit',command=root.destroy)
    menubar.add_cascade(label='Page',menu=filemenu)
    root.config(menu=menubar)

    root.overrideredirect(True)
    root.geometry("{0}x{1}+0+0".format(root.winfo_screenwidth(), root.winfo_screenheight()))

    root.mainloop()
Calendar()

它的工作原理是允许教师键入时间表，然后我的目标是保存时间表，以便将来可以引用它（因此不会在每次关闭时重置）。达到目标的有效方法是什么？

如我所知，如果我对这个问题的解释不好，请随时提问。

在这种情况下使用文本文件存储数据的最佳方法？

0 个答案: