我的数据库正在保存公司拨打的电话。
我需要进行一次选择查询,以选择所有唯一身份的人,并为每个人选择:
我尝试了此操作,但选择了入站和出站电话。
病态的解释如何查看呼叫何时入站或出站。
填满OriginationDevice
后,将对其进行DestinationName
的入站呼叫。
填满DestinationDevice
后,将向OriginationName
发出呼出电话。
我需要每个唯一的DestinationName
或OriginationName
并列出入站,出站和总通话次数,当然还有平均通话时间。
我走的很远,但似乎无法在一个查询中获得入站和出站。
查看我的SQL Fiddle,您可以在其中帮助我!
谁能帮助我获得每个人的平均通话时间,呼出电话,呼入电话和总通话次数?
我的查询尝试:
SELECT * FROM (
SELECT
IFNULL (SUM( CASE WHEN OriginationDevice != '' AND ConnectTime != '' THEN
DATEDIFF(ConnectTime, EndTime) ELSE null END ) / COUNT(case when
OriginationDevice <> '' then 1 else null end), 0) as calltime,
COUNT(case when OriginationDevice != '' then 1 else null end) as inbound,
COUNT(case when DestinationDevice != '' AND OriginationDevice = '' then 1
else null end) as outbound,
COUNT(*) as total,
DestinationName
FROM calls WHERE (YEAR(EndTime) = 2018 AND MONTH(EndTime) = 12) and
(OriginationDevice != '' or DestinationDevice != '')
AND ConnectTime != '' GROUP BY DestinationName
) as t1
WHERE total > 0 ORDER BY total DESC, calltime
这是表sql:
CREATE TABLE IF NOT EXISTS `calls` (
`OriginationName` varchar(200) NOT NULL,
`DestinationName` varchar(200) NOT NULL,
`ConnectTime` DATETIME NOT NULL,
`EndTime` DATETIME NOT NULL,
`OriginationDevice` varchar(200) NOT NULL,
`DestinationDevice` varchar(200) NOT NULL
) DEFAULT CHARSET=utf8;
INSERT INTO `calls` (`OriginationName`, `DestinationName`, `ConnectTime`, `EndTime`, `OriginationDevice`, `DestinationDevice`) VALUES
('Person 1', 'Person 5', '2018-12-11 11:26:12', '2018-12-11 11:26:18', '243', '(call routing)'),
('Person 2', 'Person 3', '2018-12-11 10:16:12', '2018-12-11 10:16:54', '', '(call routing)'),
('Person 5', 'Person 1', '2018-12-11 10:21:12', '2018-12-11 10:22:22', '', ''),
('Person 2', 'Person 1', '2018-12-11 11:26:12', '2018-12-11 11:26:52', '233', ''),
('Person 1', 'Person 4', '2018-12-11 12:26:12', '2018-12-11 12:28:25', '456', ''),
('', 'Person 1', '2018-12-11 14:56:12', '2018-12-11 14:57:24', '', '(call routing)'),
('Person 3', '', '2018-12-11 15:26:12', '2018-12-11 15:26:37', '223', '');
我的预期结果在查询中。
答案 0 :(得分:0)
这应该按照您的要求进行:
SELECT
Person,
SUM(case when typology = 'outbounds' then calls_number else 0 end) as outbounds,
SUM(case when typology = 'inbounds' then calls_number else 0 end) as inbounds,
SUM(calls_number) as calls_number,
case when SUM(calls) = 0 then 0 else SUM(callTime) / SUM(calls) end as avgCallTime
FROM(
SELECT
OriginationName as Person,
SUM(case
when DestinationDevice != '' and ConnectTime != '' then (EndTime - ConnectTime)
else 0 end
) as callTime,
SUM(case when DestinationDevice != '' then 1 else 0 end) as calls_number,
'outbounds' as typology
FROM calls
WHERE (YEAR(EndTime) = 2018 AND MONTH(EndTime) = 12) and ConnectTime != ''
and OriginationName != ''
GROUP BY OriginationName
union
SELECT
DestinationName,
SUM(case
when OriginationDevice != '' and ConnectTime != '' then (EndTime - ConnectTime)
else 0 end
),
SUM(case when OriginationDevice != '' then 1 else 0 end),
'inbounds' as typology
FROM calls
WHERE (YEAR(EndTime) = 2018 AND MONTH(EndTime) = 12) and ConnectTime != ''
and DestinationName != ''
GROUP BY DestinationName) as T
GROUP BY Person;
让我知道是否有问题,此示例工作https://sqltest.net/#386096