Question

我正在寻找一种排序大型数据集的方法，该方法类似于我在下面提供的方法，而无需使用大型循环。我正在寻找将“ 439190”的数据排序为多个数组，每个数组中仅包含“ colorid”之一。我一直在浏览所有的过滤，映射和归约方法，但没有成功，如果有人能指出正确的方向，那将是很好的。

原始Json输出：

{ '439190':
   [ { assetid: '9354886749',
       classid: 439190,
       colorid: '1650467837',
       category: 'student',
       favouritecolor: '439190-Red' },
     { assetid: '9354886743',
       classid: 439190,
       colorid: '1650467837',
       category: 'student',
       favouritecolor: '439190-Red' },
     { assetid: '9354886777',
       classid: 439190,
       colorid: '1650467837',
       category: 'student',
       favouritecolor: '439190-Red' },
     { assetid: '9354886726',
       classid: 439190,
       colorid: '1650746832',
       category: 'student',
       favouritecolor: '439190-Blue' },
     { assetid: '9354886755',
       classid: 439190,
       colorid: '1650746832',
       category: 'student',
       favouritecolor: '439190-Blue' },
     { assetid: '9354886753',
       classid: 439190,
       colorid: '1650746832',
       category: 'student',
       favouritecolor: '439190-Blue' },
     { assetid: '9354869964',
       classid: 439190,
       colorid: '1649236744',
       category: 'student',
       favouritecolor: '439190-Green' },
     { assetid: '9354869970',
       classid: 439190,
       colorid: '1649236744',
       category: 'student',
       favouritecolor: '439190-Green' },
     { assetid: '9354869963',
       classid: 439190,
       colorid: '1649236744',
       category: 'student',
       favouritecolor: '439190-Green' },
     { assetid: '9354886738',
       classid: 439190,
       colorid: '1651234125',
       category: 'student',
       favouritecolor: '439190-Yellow' },
     { assetid: '9354886773',
       classid: 439190,
       colorid: '1651234125',
       category: 'student',
       favouritecolor: '439190-Yellow' },
     { assetid: '9354886739',
       classid: 439190,
       colorid: '1651234125',
       category: 'student',
       favouritecolor: '439190-Yellow' },
     { assetid: '9354869966',
       classid: 439190,
       colorid: '1651726369',
       category: 'student',
       favouritecolor: '439190-Pink' },
     { assetid: '9354886767',
       classid: 439190,
       colorid: '1651726369',
       category: 'student',
       favouritecolor: '439190-Pink' },
     { assetid: '9354886727',
       classid: 439190,
       colorid: '1651726369',
       category: 'student',
       favouritecolor: '439190-Pink' },
     { assetid: '9354886763',
       classid: 439190,
       colorid: '1642929857',
       category: 'student',
       favouritecolor: '439190-Orange' },
     { assetid: '9354886722',
       classid: 439190,
       colorid: '1642929857',
       category: 'student',
       favouritecolor: '439190-Orange' },
     { assetid: '9354886762',
       classid: 439190,
       colorid: '1642929857',
       category: 'student',
       favouritecolor: '439190-Orange' } ],

预期的输出（大致但希望您能理解）：

{ '439190':
   [ [ { assetid: '9354886749',
         classid: 439190,
         colorid: '1650467837',
         category: 'student',
         favouritecolor: '439190-Red' },
       { assetid: '9354886726',
         classid: 439190,
         colorid: '1650746832',
         category: 'student',
         favouritecolor: '439190-Blue' },
       { assetid: '9354869964',
         classid: 439190,
         colorid: '1649236744',
         category: 'student',
         favouritecolor: '439190-Green' },
       { assetid: '9354886738',
         classid: 439190,
         colorid: '1651234125',
         category: 'student',
         favouritecolor: '439190-Yellow' },
       { assetid: '9354869966',
         classid: 439190,
         colorid: '1651726369',
         category: 'student',
         favouritecolor: '439190-Pink' },
       { assetid: '9354886763',
         classid: 439190,
         colorid: '1642929857',
         category: 'student',
         favouritecolor: '439190-Orange' } ],

     [ { assetid: '9354886743',
         classid: 439190,
         colorid: '1650467837',
         category: 'student',
         favouritecolor: '439190-Red' },
       { assetid: '9354886755',
         classid: 439190,
         colorid: '1650746832',
         category: 'student',
         favouritecolor: '439190-Blue' },
       { assetid: '9354869970',
         classid: 439190,
         colorid: '1649236744',
         category: 'student',
         favouritecolor: '439190-Green' },
       { assetid: '9354886773',
         classid: 439190,
         colorid: '1651234125',
         category: 'student',
         favouritecolor: '439190-Yellow' },
       { assetid: '9354886767',
         classid: 439190,
         colorid: '1651726369',
         category: 'student',
         favouritecolor: '439190-Pink' },
       { assetid: '9354886722',
         classid: 439190,
         colorid: '1642929857',
         category: 'student',
         favouritecolor: '439190-Orange' } ],

     [ { assetid: '9354886777',
         classid: 439190,
         colorid: '1650467837',
         category: 'student',
         favouritecolor: '439190-Red' },
       { assetid: '9354886753',
         classid: 439190,
         colorid: '1650746832',
         category: 'student',
         favouritecolor: '439190-Blue' },
       { assetid: '9354869963',
         classid: 439190,
         colorid: '1649236744',
         category: 'student',
         favouritecolor: '439190-Green' },
       { assetid: '9354886739',
         classid: 439190,
         colorid: '1651234125',
         category: 'student',
         favouritecolor: '439190-Yellow' },
       { assetid: '9354886727',
         classid: 439190,
         colorid: '1651726369',
         category: 'student',
         favouritecolor: '439190-Pink' },
       { assetid: '9354886762',
         classid: 439190,
         colorid: '1642929857',
         category: 'student',
         favouritecolor: '439190-Orange' } ] ],

我当前的代码：

for(i in json){
  test = Array.from(new Set(json[i].map(item => item.colorid)))
  .map( colorid=> {
    return {
      "assetid":json[i].find(s => s.colorid=== colorid).assetid,
      "classid":json[i].find(s => s.colorid=== colorid).classid,
      "colorid":colorid,
      "category":json[i].find(s => s.colorid=== colorid).category,
      "favouritecolor":json[i].find(s => s.colorid=== colorid).favouritecolor
    };
  });
  console.log(test);
}

它确实将结果过滤为仅包含唯一的颜色，并且保留所有关键数据，尽管它仅返回一个数组。至此，我一直没有找到有效的方法（不使用多个嵌入式循环）来获得上面显示的预期输出。任何改进我的代码或为我指明正确方向的帮助将不胜感激：）

Answer 1

我只是将其组合在一起以给您一些指示，但是类似的东西应该会有所帮助。您需要创建一个reduce函数，该函数具有一个数组数组作为累加器。然后检查每个数组以查看是否存在匹配的元素，并将其添加到不存在的第一个数组中。如果每个数组中都存在该元素，则推一个新数组。

const array = [1, 2, 3, 4, 6, 4, 5, 6, 4];

const listReducer = (accumulator, currentValue) => {
    let pushed = false;
    accumulator.forEach((list) => {
        if (!list.includes(currentValue)) {
            list.push(currentValue);
            pushed = true;
        }
    });
    if (!pushed) {
        accumulator.push([currentValue]);
    }
    return accumulator;
}

const startingValue = [];

console.log(array.reduce(listReducer, startingValue));

Sort方法将json排序为包含唯一值数组的json

1 个答案: