Question

我想评估一个if语句，以确定是否在此链接中添加一个类（除up_vote之外）：

<%= link_to "&uArr;".html_safe, video_votes_path( :video_id => video.id, :type => "up" ), :method => :post, :remote => true, :class => 'up_arrow' %>

我该怎么做？

Answer 1

直接进行内联：

<%= link_to "&uArr;".html_safe, video_votes_path( :video_id => video.id, :type => "up" ), :method => :post, :remote => true, :class => "up_arrow #{condition ? 'other_class' : ''}" %>

Answer 2

这样的东西？

<%
html_class = 'up_arrow'
if some_condition == true
  html_class += 'another-class'
end
%>
<%=  link_to "&uArr;".html_safe, video_votes_path( :video_id => video.id, :type => "up" ), :method => :post, :remote => true, :class => html_class %>

但是将它重构为帮助者或其他东西都不会受到伤害。

Answer 3

<% 
class_name = "up_vote"
 if condition
   class_name << " another_class" 
 end
%>


<%= link_to "&uArr;".html_safe, video_votes_path( :video_id => video.id, :type => "up" ), :method => :post, :remote => true, :class => class_name %>

在添加其他类之前请注意该空格。这就是你在HTML中有多个类的方法

嵌入式ruby if语句

3 个答案: