我有一个表,其中包含用逗号分隔的URL列表。忽略应该更新架构的事实。以下两个语句均有效:
SELECT id FROM website WHERE url LIKE '%example.com%';
SELECT id FROM website WHERE FIND_IN_SET('example.com', url);
是否有衡量查询性能的好方法?有没有更好的方法(无需更新架构)?
使用“说明”,我得到以下结果:
+-------------+--------+---------+------+----------+
| select_type | type | key | rows | filtered |
+-------------+--------+---------+------+----------+
| SIMPLE | ALL | NULL | 5 | 20.00 | (LIKE)
| SIMPLE | ALL | NULL | 5 | 100.00 | (FIND_IN_SET)
+-------------+-------+----------+------+----------+
答案 0 :(得分:0)
在MariaDB中,您可以在查询后看到SET profiling=ON;
和SHOW PROFILE;
。
样品
MariaDB [test]> SET profiling=ON;
Query OK, 0 rows affected (0.000 sec)
MariaDB [test]> SELECT FIND_IN_SET('2', '1,2,3,4,5');
+-------------------------------+
| FIND_IN_SET('2', '1,2,3,4,5') |
+-------------------------------+
| 2 |
+-------------------------------+
1 row in set (0.000 sec)
MariaDB [test]> SHOW PROFILE;
+--------------------------------+----------+
| Status | Duration |
+--------------------------------+----------+
| Starting | 0.000025 |
| Waiting for query cache lock | 0.000005 |
| Init | 0.000004 |
| Checking query cache for query | 0.000047 |
| Checking permissions | 0.000007 |
| Opening tables | 0.000011 |
| After opening tables | 0.000007 |
| Init | 0.000014 |
| Optimizing | 0.000012 |
| Executing | 0.000010 |
| End of update loop | 0.000005 |
| Query end | 0.000003 |
| Commit | 0.000004 |
| Closing tables | 0.000003 |
| Starting cleanup | 0.000004 |
| Freeing items | 0.000006 |
| Updating status | 0.000014 |
| Reset for next command | 0.000004 |
+--------------------------------+----------+
18 rows in set (0.000 sec)
MariaDB [test]>