从包含特定关键字的json数据中删除所有对象

Question

我只是在寻找最佳实践，以删除从包含特定术语/关键字的json数据中删除所有对象的方法。

我的json数据看起来像这样

json = [{
 "name":"John",
 "age":30,
 "cars":"BMW"
},
{
 "name":"Micheal",
 "age":30,
 "cars":"Ford,BMW"
},
{
 "name":"Andy",
 "age":29,
 "cars":"Ford"
},
{
 "name":"Andy",
 "age":29,
 "cars":"Ford,Toyota"
}];

我要删除关键字为“ BMW”的对象。

Answer 1

您可以简单地使用Array.filter()：

var arr = [{ "name":"John", "age":30, "cars":"BMW" }, { "name":"Micheal", "age":30, "cars":"Ford,BMW" }, { "name":"Andy", "age":29, "cars":"Ford" }, { "name":"Andy", "age":29, "cars":"Ford,Toyota" }];

var result = arr.filter(({cars})=> !cars.includes("BMW"));

console.log(result);

Answer 2

对于从包含字符串的对象数组中删除元素，Array.filter是最佳解决方案，但其另一个替代可以是Array.reduce，如下所示：< / p>

var arr =[{ "name":"John", "age":30, "cars":"BMW" }, { "name":"Micheal", "age":30, "cars":"Ford,BMW" }, { "name":"Andy", "age":29, "cars":"Ford" }, { "name":"Andy", "age":29, "cars":"Ford,Toyota" }];

var newarr = arr.reduce((acc, elem) => !elem.cars.includes("BMW") ? acc.concat(elem) : acc, []);

console.log(newarr);