此表需要此结果。 这是3列,我想要3个带有嵌套节点的结果。 真的,我希望每个节点都具有self和parent这样的结果
ID/ Number/SelfRef
21092 100 NULL
21093 50 NULL
21094 30 21093
21095 20 21093
21096 -30 21093
21097 5 21095
21098 15 21095
21099 -5 21095
我需要这个结果
21097 5 21097
21097 5 21095
21097 5 21093
这是我的逻辑
答案 0 :(得分:0)
这对我有用
;WITH
cte1 AS
( -- Recursively build the relationship tree
SELECT SelfRef
, ID
, AscendentLevel = 1
FROM [Kharid].[IdentityGharardadKalaTedad]
UNION ALL
SELECT t.SelfRef
, cte1.ID
, AscendentLevel = cte1.AscendentLevel + 1
FROM cte1
INNER JOIN [Kharid].[IdentityGharardadKalaTedad] t ON t.ID = cte1.SelfRef
),
cte2 AS
( -- Now find the ultimate parent
SELECT SelfRef
, ID
, rn = ROW_NUMBER() OVER (PARTITION BY ID ORDER BY AscendentLevel DESC)
FROM cte1
)
SELECT *
FROM cte2
Order by id