Question

我的输入是：

group;|line1_1|line2_2|line3_3

我想提取信息行1，行2，行3，如下所示： line1，line2，line3

我已经尝试使用以下命令但无法执行：

LINE="group;|line1_1|line2_2|line3_3"; echo $LINE | awk -F ";" '{print $2}' | awk -F "|" '{for(i=1;i<=NF;++i){print $i | system("cut -d _ -f1")}}'

Answer 1

考虑到您的实际Input_file与所示示例相同。您能不能试一下。

awk -F'|' '{for(i=2;i<=NF;i++){sub(/_.*/,"",$i);val=val?val OFS $i:$i};print val;val=""}'  OFS=","  Input_file

第二个解决方案： ：此处仅使用sub中的gsub和awk。

awk '{sub(/^[^|]*\|/,"");gsub(/_[0-9]\|/,",");sub(/_[0-9]$/,"")} 1' Input_file
OR
awk '{gsub(/^[^|]*\||_[0-9]$/,"");gsub(/_[0-9]\|/,",")} 1' Input_file

输出如下。

line1,line2,line3

说明： 现在添加上述代码的说明。

awk -F'|' '                    ##Setting field separator as | here for all lines.
{                              ##Starting block here.
  for(i=2;i<=NF;i++){          ##Starting for loop starting form i=2 to till value of NF here.
    sub(/_.*/,"",$i)           ##Using sub for substitution from _ to till everything with NULL in value of $i.
    val=val?val OFS $i:$i      ##Creating variable val and concatenate its own value if it is having NON ZERO value else save in it for 1st time.
  }                            ##Close for loop block here.
  print val                    ##Printing value of val here.
  val=""                       ##Nullifying value of variable val here.
}'  OFS=","  Input_file        ##Setting value of OFS to comma here and mentioning Input_file name here.

使用awk提取信息

1 个答案: