我正在尝试将GPIO引脚读取为输入，同时使用Tkinter作为图形模块来控制输出。到目前为止，还不能很好地证明这一点。我克服了循环问题，解决了“ while True”自变量替换为after但sleep问题锁定程序的问题。我对python的了解不够深，无法了解.after的正确语法。我认为使用全局方法可能会有所帮助，但是我不确定如何用Python编写它。我更多是C，C＃和C ++开发人员，而我对Python还是比较陌生。因此，到目前为止，我将发布我的代码，如果有人有任何想法，我肯定会在听！
import tkinter as tk
import tkinter.font
import RPi.GPIO as GPIO
from random import randint
from tkinter import Tk, Button, NSEW
from gpiozero import LED, Button
from signal import pause
win = tk.Tk()
win.title("ARBOR 4.0")
myFont = tkinter.font.Font(family = 'Helvectica', size = 24, weight = "bold")
Relay1 = LED(5) #Left Bin Selection
Relay2 = LED(6) #Right Bin Selection
Relay3 = LED(13) #Latch Release
Relay4 = LED(12) #General Bin Selection Signal
LimitSW = Button(26) #Sense Status of Door
SensePin = Button(16) #3.3V Return for System Use Status
SprinklerSense = Button(14) #Sprinkler sense
FireSense = Button(19) #Fire sense circuit
GPIO.setmode(GPIO.BCM)
# GPIO.setmode(GPIO.BOARD) Perhaps Broadcom is problem
GPIO.setup(26, GPIO.IN)
GPIO.setup(16, GPIO.IN)
GPIO.setup(26, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)
GPIO.setup(16, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)
GPIO.setup(14, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)
GPIO.setup(19, GPIO.IN, pull_up_down=GPIO.PUD_DOWN)
POLLING_DELAY = 3000
def get_gpio_input():
return randint(1, 10) < 3
def check_status():
input_state1 = GPIO.input(26)
input_state2 = GPIO.input(16)
input_state3 = GPIO.input(14)
input_state4 = GPIO.input(19)
if input_state1 == True:
if input_state2 == True:
LimitSW["text"] = "System In Use"
else if input_state3 == True;
LimitSW["text"] = "System Cleaning, Please Wait!"
win.after(1)
else if input_state4 == True;
LimitSW["text"] = "Fire Alert! Please Wait!" bg='red'
else:
LimitSW["text"] = "System Available"
Relay1.off()
Relay2.off()
Relay3.off()
Relay4.off() # Reset all relays to off
def selectOption1():
if Relay1.is_lit:
Relay1.off()
paperButton["text"] = "Paper"
else:
if LimitSW["text"] == "System Available":
Relay1.on() # Signal Left Bin Selection
Relay3.on() # Open Latch
LimitSW["text"] = "System In Use"
paperButton["text"] = "Please Wait!"
win.after(1000)
Relay1.off() # Signal Left Bin Selection
Relay3.off() # Open Latch
paperButton["text"] = "Paper"
LimitSW["text"] = "System Available"
def selectOption2():
if Relay2.is_lit:
Relay1.off()
plasticButton["text"] = "Plastic"
else:
if LimitSW["text"] == "System Available":
Relay2.on() # Signal Right Bin Selection
Relay3.on() # Open Latch
LimitSW["text"] = "System In Use"
plasticButton["text"] = "Please Wait!"
win.after(1000)
Relay2.off() # Signal Left Bin Selection
Relay3.off() # Open Latch
plasticButton["text"] = "Plastic"
LimitSW["text"] = "System Available"
def selectOption3():
if Relay2.is_lit:
Relay2.off()
glassButton["text"] = "Glass/Metal"
else:
if LimitSW["text"] == "System Available":
Relay2.on() # Signal Right Bin Selection
Relay3.on() # Open Latch
LimitSW["text"] = "System In Use"
glassButton["text"] = "Pleae Wait!"
win.after(1000)
Relay2.off() # Signal Left Bin Selection
Relay3.off() # Open Latch
glassButton["text"] = "Glass/Metal"
LimitSW["text"] = "System Available"
def selectOption4():
if Relay4.is_lit:
Relay3.off()
Relay4.off()
generalButton["text"] = "General Waste"
else:
if LimitSW["text"] == "System Available":
Relay4.on() # Signal Home Bin Selection
Relay3.on() # Open Latch
LimitSW["text"] = "System In Use"
generalButton["text"] = "Pleae Wait!"
win.after(1000)
Relay4.off() # Signal Left Bin Selection
Relay3.off() # Open Latch
generalButton["text"] = "General Waste"
LimitSW["text"] = "System Available"
def exitProgram():
win.quit()
win.destroy()
LimitSW=tk.Button(win, text='System Available', font=myFont, bg='orange', height=2, width=36)
LimitSW.grid(row=0, sticky=tk.NSEW)
paperButton=tk.Button(win, text='Paper', font=myFont, command=selectOption1, bg='blue', height=2, width=36)
paperButton.grid(row=1, sticky=tk.NSEW)
plasticButton=tk.Button(win, text='Plastic', font=myFont, command=selectOption2, bg='red', height=2, width=36)
plasticButton.grid(row=2, sticky=tk.NSEW)
glassButton=tk.Button(win, text='Glass/Metal', font=myFont, command=selectOption3, bg='green', height=2, width=36)
glassButton.grid(row=3, sticky=tk.NSEW)
generalButton=tk.Button(win, text='General Waste', font=myFont, command=selectOption4, bg='purple', height=2, width=36)
generalButton.grid(row=4, sticky=tk.NSEW)
exitButton=tk.Button(win, text='Exit', font=myFont, command=exitProgram, bg='purple', height=2, width=36)
exitButton.grid(row=5, sticky=tk.NSEW)
win.after(0, check_status)
win.mainloop()
这是一个回收界面，如果有人可以完成任务，我真的需要帮助。它在使用5英寸触摸屏的Raspberry Pi上运行。如果有人对我有任何建议，请先感谢！
答案 0 :(得分：0)
您可以在无限while循环中执行一个线程，该线程检查引脚的状态（ON / OFF）并相应地执行操作。 您也可以设置一个中断，但是这会有些复杂，并且可能会导致中断。您可以参考以下代码并在此处和此处进行调整以满足您的需求：
import RPi.GPIO as GPIO
import time
import tkinter as tk
class Application(tk.Frame):
def __init__(self, master=None):
super().__init__(master)
self.pack()
self.create_widgets()
self.pi_button()
def create_widgets(self):
self.hi_there = tk.Button(self)
self.hi_there["text"] = "Hello World\n(click me)"
self.hi_there["command"] = lambda: self.say_hi('tk button pressed')
self.hi_there.pack(side="top")
self.quit = tk.Button(self, text="QUIT", fg="red",
command=root.destroy)
self.quit.pack(side="bottom")
def pi_button(self):
#Setup GPIO for input
GPIO.setmode(GPIO.BCM)
GPIO.setup(18, GPIO.IN, pull_up_down=GPIO.PUD_UP)
self.input_state = GPIO.input(18)
#Check to see if button is pressed, if it is print notification
if self.input_state == False:
self.say_hi('rpi button pressed')
#Use tks main loop as a while loop to call for a check every .5 seconds
self.after(500, self.pi_button)
def say_hi(self, text):
print(text)
root = tk.Tk()
app = Application(master=root)
app.mainloop()