问题： FoodCorner的家根据订单向其客户提供素食和非素食套餐。
素食套餐每盘120卢比，非素食套餐每盘150卢比。他们的非素食组合真的很有名，他们比素食组合获得更多的非素食组合订单。除了每盘食物的费用外，还根据从餐厅到送货点的距离（以公里为单位）向顾客收取送货上门费用。运费如下：
距离（单位：公里），送货费，单位：Rs / km 前3公里Rs 0 接下来的3公里Rs 3 对于剩余的6卢比
给出食物的类型，数量（盘数）以及从餐厅到送货点的距离（以kms为单位），编写一个python程序来计算要由客户支付的最终账单金额。
以下信息必须用于检查客户提供的数据的有效性：
对于素食者，食物类型必须为“ V”，对于非素食者，食物类型必须为“ N”。 以公里为单位的距离必须大于0。 订购数量应最少为1。 如果任何输入无效，则账单金额应被视为-1。
我的解决方案：
def calculate_bill_amount(food_type,quantity_ordered,distance_in_kms):
bill_amount=0.0
if distance_in_kms >= 0.0 and distance_in_kms <= 3.0:
if food_type == "V" and quantity_ordered >= 1:
bill_amount = 120*quantity_ordered
elif food_type =="N" and quantity_ordered >= 1:
bill_amount = 150*quantity_ordered
else:
bill_amount = -1
elif distance_in_kms > 3.0 and distance_in_kms <= 6.0:
if food_type == "V" and quantity_ordered>=1:
bill_amount = 120*quantity_ordered + 3*distance_in_kms
elif food_type == "N" and quantity_ordered>=1:
bill_amount = 150*quantity_ordered + 3*distance_in_kms
else:
bill_amount = -1
elif distance_in_kms > 6.0:
if food_type == "V" and quantity_ordered>=1:
bill_amount = 120*quantity_ordered + 6*distance_in_kms
elif food_type == "N" and quantity_ordered>=1:
bill_amount = 150*quantity_ordered + 6*distance_in_kms
else:
bill_amount = -1
else:
bill_amount = -1
return bill_amount
bill_amount=calculate_bill_amount("N",1,7.0)
print(bill_amount)
答案 0 :(得分：0)
请根据每公里的费用而不是直接从距离计算运费。请找到以下代码。
defcalculate_bill_amount（食品类型，数量排序，距离_公里）：
if food_type == 'V' and quantity_ordered>0:
food_cost=120*quantity_ordered
elif food_type== 'N' and quantity_ordered>0:
food_cost=150*quantity_ordered
else:
return -1
if distance_in_kms<0:
return -1
if distance_in_kms>6.0:
delivery_charge = (distance_in_kms-6)*6.0+ 9.0
elif distance_in_kms>3.0 and distance_in_kms<=6.0:
delivery_charge=(distance_in_kms-3)*3.0
else:
delivery_charge=0
bill_amount=food_cost+delivery_charge
return bill_amount
bill_amount = calculate_bill_amount（“ N”，-1,7.0）
打印（帐单金额）
答案 1 :(得分：0)
首先，感谢您发布整个问题和整个解决方案。并不是每个人都是高手，是的，我们需要整个代码来了解我们的需求。在过去的一个小时中，我一直被一个相同的问题困扰，因此一直在寻找解决方案，但只能找到人们在谈论编写“较短的代码”。无论如何，我找到了解决方案，这是适用于所有测试用例的解决方案。
def calculate_bill_amount(food_type,quantity_ordered,distance_in_kms):
bill_amount=0
if(distance_in_kms<=0 or quantity_ordered<1):
bill_amount=-1
else:
if(food_type=="N"):
if(distance_in_kms<=3):
bill_amount=(150*quantity_ordered)+(0*distance_in_kms)
elif(distance_in_kms>3 and distance_in_kms<=6):
bill_amount=(150*quantity_ordered)+(3*(distance_in_kms-3))
else:
bill_amount=((150*quantity_ordered)+((distance_in_kms-6)*6+9))
elif(food_type=="V"):
if(distance_in_kms<=3):
bill_amount=(120*quantity_ordered)+(0*distance_in_kms)
elif(distance_in_kms>3 and distance_in_kms<=6):
bill_amount=(120*quantity_ordered)+(3*(distance_in_kms-3))
else:
bill_amount=(120*quantity_ordered)+(9+6*(distance_in_kms-6))
else:
bill_amount=-1
return bill_amount
bill_amount=calculate_bill_amount("n",2,8)
print(bill_amount)
答案 2 :(得分：0)
def calculate_bill_amount(food_type,quantity_ordered,distance_in_kms):
bill_amount=0
if(food_type=="N" and quantity_ordered>=1 and distance_in_kms>0):
if(distance_in_kms>0 and distance_in_kms<=3):
bill_amount=150*quantity_ordered
elif(distance_in_kms >3 and distance_in_kms<=6)
bill_amount=150+(3*(distance_in_kms-3))*quantity_ordered
else:
bill_amount=150+(6*(distance_in_kms-6))*quantity_ordered
elif (food_type=="V" and quantity_ordered>=1 and distance_in_kms>0):
if(distance_in_kms>0 and distance_in_kms<=3):
bill_amount=120*quantity_ordered
elif(distance_in_kms>3 and distance_in_kms<=6):
bill_amount=120+(3*(distance_in_kms-3))*quantity_ordered
else:
bill_amount=120+(6*(distance_in_kms-6))*quantity_ordered
else:
bill_amount=-1
return bill_amount
bill_amount = calculate_bill_amount（“ N”，1,7） 打印（帐单金额）
答案 3 :(得分：0)
def calculate_bill_amount(food_type, quantity_ordered, distance_in_kms):
bill_amount = 0
vegComboPrice = 120
nonVegComboPrice = 150
if quantity_ordered > 0 and distance_in_kms > 0:
if food_type == "V":
vegSubTotal = vegComboPrice * quantity_ordered
if distance_in_kms <= 3:
bill_amount = vegSubTotal
elif distance_in_kms > 3 and distance_in_kms <= 6:
distanceCharge = distance_in_kms - 3
distanceCharge *= 3
bill_amount = vegSubTotal + distanceCharge
else:
distanceCharge = distance_in_kms - 6
distanceCharge *= 6
bill_amount = vegSubTotal + distanceCharge + 9
elif food_type == "N":
nonVegSubTotal = nonVegComboPrice * quantity_ordered
if distance_in_kms <= 3:
bill_amount = nonVegSubTotal
elif distance_in_kms > 3 and distance_in_kms <= 6:
distanceCharge = distance_in_kms - 3
distanceCharge *= 3
bill_amount = nonVegSubTotal + distanceCharge
else:
distanceCharge = distance_in_kms - 6
distanceCharge *= 6
bill_amount = nonVegSubTotal + distanceCharge + 9
else:
bill_amount = -1
else:
bill_amount = -1
return bill_amount
bill_amount = calculate_bill_amount("V",1,1)
print(bill_amount)
答案 4 :(得分：0)
def calculate_bill_amount(food_type,quantity_ordered,distance_in_kms):
bill_amount=0
if food_type == 'N' and quantity_ordered !=0 and distance_in_kms >0:
bill_amount=150*quantity_ordered if distance_in_kms < 4 else 150*quantity_ordered+(distance_in_kms-3)*3 if 3 < distance_in_kms <=6 else 150*quantity_ordered+(distance_in_kms-6)*6+9
return bill_amount
elif food_type == 'V' and quantity_ordered !=0 and distance_in_kms >0:
bill_amount=120*quantity_ordered if distance_in_kms < 4 else 120*quantity_ordered+(distance_in_kms-3)*3 if 3 < distance_in_kms <=6 else 120*quantity_ordered+(distance_in_kms-6)*6+9
return bill_amount
else:
bill_amount=-1
return bill_amount
bill_amount=calculate_bill_amount("n",2,8)
print(bill_amount)
答案 5 :(得分：0)
def calculate_bill_amount(food_type,quantity_ordered,distance_in_kms):
bill_amount=0
#write your logic here
if((food_type =="V" or food_type=="N") and (quantity_ordered >0 and distance_in_kms>0)):
if(food_type == "V"):
bill_amount = 120 * quantity_ordered
elif(food_type =="N"):
bill_amount = 150 * quantity_ordered
else:
bill_amount=-1
if(0<distance_in_kms<=3):
bill_amount +=0
elif(3<distance_in_kms<=6):
bill_amount += 3*(distance_in_kms-3)
else:
bill_amount +=(9+6*(distance_in_kms-6))
else:
bill_amount = -1
return bill_amount
#Provide different values for food_type,quantity_ordered,distance_in_kms and test your program
bill_amount=calculate_bill_amount("N",2,7)
print(bill_amount)
答案 6 :(得分：0)
def calculate_bill_amount(food_type,quantity_ordered,distance_in_kms):
bill_amount=0
delivery_charge = 0
if((food_type=="N" or food_type=="V") and quantity_ordered >=1 and distance_in_kms > 0):
if(distance_in_kms > 3 and distance_in_kms <=6):
delivery_charge = (distance_in_kms-3)*3
elif(distance_in_kms > 6):
delivery_charge = (distance_in_kms-6)*6 + 9
if(food_type == "N"):
bill_amount = quantity_ordered*150 + delivery_charge
elif(food_type == "V"):
bill_amount = quantity_ordered*120 + delivery_charge
else:
bill_amount = -1
return bill_amount
bill_amount=calculate_bill_amount("N",2,7)
print(bill_amount)