Ruby on Rails:我无法创建新用户

时间:2018-12-11 07:57:56

标签: ruby-on-rails

当我使用应用程序目录上的$ curl -X POST '{"user": {"name": "hogehoge", "email": "hogehoge@gmail.com", "icon_url": "hogehoge", "location": "hogehgoe", "password": "hogehoge"}}' localhost:3000/v1/users发送到终端以创建新用户时,出现错误。

{
  "status": 400,
  "error": "Bad Request",
  "exception": "#<ActionController::ParameterMissing: param is missing or the value is empty: user>",
  ・・・
  ・・・
  ・・・
}

在服务器日志上

Started POST "/v1/users" for 127.0.0.1 at 2018-12-11 16:55:56 +0900
Processing by V1::UsersController#create as JSON
  Parameters: {"name"=>"hogehoge", "email"=>"hogehoge@gmail.com", "icon_url"=>"hogehoge", "location"=>"hogehoge", "password"=>"[FILTERED]"}
Completed 400 Bad Request in 1ms



ActionController::ParameterMissing (param is missing or the value is empty: user):

app/controllers/v1/users_controller.rb:52:in `user_params'
app/controllers/v1/users_controller.rb:20:in `create'

我认为user_params对正确的参数感到满意,但事实并非如此。

这是我的user_controller.rb

module V1
  class UsersController < ApiController
    before_action :set_user, only: [:show, :update, :destroy]
    skip_before_action :authenticate_user_from_token!, only: [:show, :index, :create]



    # POST /users
    def create
      @user = User.new(user_params)

      if @user.save
        render json: @user, serializer: V1::UserSerializer
      else
        render json: @user.errors, status: :unprocessable_entity
      end
    end


    private
    # Use callbacks to share common setup or constraints between actions.
    def set_user
      @user = User.find(params[:id])
    end

    # Only allow a trusted parameter "white list" through.
    def user_params
      params.require(:user).permit(:name, :email, :location, :icon_url, :password)
      p params
    end
  end
end

为什么HTTP向我发送了400个错误的状态代码?


正如您所说,我将带有此JSON参数的终端发送到localhost:3000/v1/users

{
 "user": 
    {
    "name": "hogehoge",
    "email": "hogehoge@gmail.com",
    "icon_url": "hogehoge",
    "location": "hogehoge",
    "password": "hogehoge"
    }
}   

但是现在HTTP状态向我发送了500个内部服务器错误。 这是一个新的错误代码。

Started POST "/v1/users" for 127.0.0.1 at 2018-12-11 17:33:50 +0900
Processing by V1::UsersController#create as JSON
  Parameters: {"user"=>{"name"=>"hogehoge", "email"=>"hogehoge@gmail.com", "icon_url"=>"hogehoge", "location"=>"hogehoge", "password"=>"[FILTERED]"}}
<ActionController::Parameters {"user"=><ActionController::Parameters {"name"=>"hogehoge", "email"=>"hogehoge@gmail.com", "icon_url"=>"hogehoge", "location"=>"hogehoge", "password"=>"hogehoge"} permitted: false>, "format"=>:json, "controller"=>"v1/users", "action"=>"create"} permitted: false>
Completed 500 Internal Server Error in 34ms (ActiveRecord: 2.0ms)



ActiveModel::ForbiddenAttributesError (ActiveModel::ForbiddenAttributesError):

app/controllers/v1/users_controller.rb:20:in `create'

2 个答案:

答案 0 :(得分:0)

您的视图

您不会在参数中传递任何具有键var test = Base64.getDecoder.decode(base64); ByteArrayInputStream(test); var input_stream = new ByteArrayInputStream(test); Logger.debug(test.getClass.getSimpleName) 的哈希,

user

如果您要按form_for的形式创建用户,则该外观应为

  Parameters: {"name"=>"hogehoge", "email"=>"hogehoge@gmail.com", "icon_url"=>"hogehoge", "location"=>"hogehoge", "password"=>"[FILTERED]"}

您确定要通过输入标签传递用户参数。那么应该如何使用强参数!

答案 1 :(得分:0)

您似乎在#user_params中留下了调试代码,因此不会返回正确的对象:

# Only allow a trusted parameter "white list" through.
def user_params
  params.require(:user).permit(:name, :email, :location, :icon_url, :password)
  p params
end