我的表中有三个字段,我想通过三次连接到另一个表来更新它们。我知道我必须使用merge into
,但是找不到使用merge into
和join
且只有一个表多次的类似查询。
select
语句如下:
select * from TABLE t
inner join DESTINATION_TABLE d1
on t.CODE1 = d1.CODE
inner join DESTINATION_TABLE d2
on t.CODE2 = d2.CODE
inner join DESTINATION_TABLE d3
on t.CODE3 = d3.CODE
现在如何使用FIELD1
,FIELD2
中的字段来更新FIELD3
中的三个字段(TABLE
,d1
,d2
) ,和d3
使用merge into
?
编辑:
原始查询是:
select * from TOTAL
inner join GROUP_LEVEL_DETAIL gl1
on gl1.NAME = substr(GL, 1, instr(GL, ' -', 1))
inner join GROUP_LEVEL_DETAIL gl2
on GL2.NAME = replace(substr(GL, instr(GL, ' -', 1, 1), instr(GL, ' -', 1, 2) - instr(GL, ' -', 1, 1)), ' - ', '')
inner join GROUP_LEVEL_DETAIL gl3
on gl3.NAME = replace(substr(GL, instr(GL, '-', 1, 2), 500), '- ', '')
TOTAL
的示例数据为:
ID GL GL1_CODE GL2_CODE GL3_CODE
----- ----------------------------- ---------- ---------- -----------
1 Sample1 - Sample2 - Sample3 null null null
2 John - Jack - Harry null null null
GROUP_LEVEL_DETAIL
的示例数据为:
CODE NAME LEVEL_NO
--------- ----------- ------------
SMP1 Sample1 1
SMP2 Sample2 2
SMP3 Sample3 3
JCK1 Jack 1
JHN2 John 2
HRY3 Harry 3
我希望我的TOTAL
表在更新后变得像这样:
ID GL GL1_CODE GL2_CODE GL3_CODE
----- ----------------------------- ---------- ---------- -----------
1 Sample1 - Sample2 - Sample3 SMP1 SMP2 SMP3
2 John - Jack - Harry JCK1 JHN2 HRY3
答案 0 :(得分:1)
从您修改后的问题来看,我认为解决方案是在子查询中组装GROUP_LEVEL_DETAIL名称,以创建一个可以加入TOTAL表的键。
merge into TOTAL t
using ( select d1.code as d1_code
, d2.code as d2_code
, d3.code as d3_code
, d1.name || ' - ' ||
d2.name || ' - ' ||
d3.name as joined_code
from GROUP_LEVEL_DETAIL d1
cross join GROUP_LEVEL_DETAIL d2
cross join GROUP_LEVEL_DETAIL d3
where d1.level_no = 1
and d2.level_no = 2
and d3.level_no = 3
) d
on ( t.gl = d.joined_code )
when matched then
update
set t.gl_code1 = d.d1_code
, t.gl_code2 = d.d2_code
, t.gl_code3 = d.d3_code
USING子查询从GROUP_LEVEL_DETAIL生成记录的所有可能排列的结果集。在您进行修订之后,我加入了WHERE子句以强制执行隐含规则GL = 'level 1 - level 2 - level 3'
。您可能不希望这样做(也许并非TOTAL中的每个记录都具有有效的GL),或者扩展WHERE子句以应用关于有效组合的任何其他规则。
答案 1 :(得分:0)
当联接基于主键或唯一索引时,您应该能够执行以下操作:
--create tables and unix index
create table table1 (code number, field1 number, field2 number, field3 number);
create unique index table1_code_inx on table1 (code);
create table table2 (code number, field1 number, field2 number, field3 number);
create unique index table2_code_inx on table2 (code);
-- update data from table2 to table1
update( select a.FIELD1 A_FIELD1, a.FIELD2 A_FILED2, a.FIELD3 A_FIELD3,
b.FIELD1 B_FIELD1, b.FIELD2 B_FILED2, b.FIELD3 B_FIELD3
from TABLE1 a, TABLE2 b
where a.CODE = b.CODE )
set A_FIELD1 = B_FIELD1,
A_FILED2 = B_FILED2,
A_FIELD3 = B_FIELD3;