例如,我有:
XNamespace nsSoap = "http://www.w3.org/2003/05/soap-envelope";
XNamespace ns = "link-to-namespace";
// Look for the "Fault" element in the response. If present, there was an error.
var fault = result.Root.Element("{" + nsSoap + "}Body").Element("{" + ns_soap + "}Fault");
if (error != null)
{
var codeWithNs = error.Element("{" + nsSoap + "}Code").Element("{" + ns_soap + "}Value").Value;
var codeSplit = codeWithNs.Split(':');
var code = codeSplit.Length == 2 ? codeSplit[1] : codeSplit[0];
if (code == "InvalidUsernameOrPassword")
{
throw new InvalidUsernameOrPasswordException();
}
else
{
throw new Exception("Something went wrong.");
}
}
,并想用“换行”替换我文档中的所有Line 1 * Line 2 * Line 3
来获取此信息:
*
Line1
Line2
这可能吗?
答案 0 :(得分:0)
由于在“查找与替换”中取消选中“通配符”似乎没有什么区别,因此除了脚本之外,您似乎有两种选择:
1)手动选择每个*
和
Ctrl + 输入
或
2)应用公式来创建数据的单独版本:
=SUBSTITUTE(A1," * ",CHAR(10))