我有以下数据
+--------+
| orders |
+--------+
| S1 |
| S2 |
| S3 |
| S4 |
| S5 |
| S6 |
| S7 |
| S8 |
| S9 |
| S10 |
| S11 |
| S12 |
+--------+
我需要按以下方式返回结果-在一列中容纳五行:
+-----------------+
| Orders |
+-----------------+
| S1,S2,S3,S4,S5 |
| S6,S7,S8,S9,S10 |
| S11,S12 |
+-----------------+
没有什么可分组或将它们分成几行的。所以我分配了一个row_number,并在row_number上做了mod 5。几乎可以,但是效果不佳。
这是我尝试过的:
;with mycte as (
select
'S1' as orders
union all select
'S2'
union all select
'S3'
union all select
'S4'
union all select
'S5'
union all select
'S6'
union all select
'S7'
union all select
'S8'
union all select
'S9'
union all select
'S10'
union all select
'S11'
union all select
'S12'
)
,mycte2 as (
Select
orders
,ROW_NUMBER() over( order by orders) %5 as rownum
from mycte
)
select distinct
STUFF((
SELECT ',' + mycte2.orders
FROM mycte2
where t1.rownum= mycte2.rownum
FOR XML PATH('')
), 1, 1, '') orders
, rownum
from mycte2 t1
结果是:
+-----------+--------+
| orders | rownum |
+-----------+--------+
| S1,S3,S8 | 1 |
| S10,S4,S9 | 2 |
| S11,S5 | 3 |
| S12,S6 | 4 |
| S2,S7 | 0 |
+-----------+--------+
有人可以告诉我如何达到我想要的结果吗?
答案 0 :(得分:4)
怎么样
CREATE TABLE T
([orders] varchar(3));
INSERT INTO T
([orders])
VALUES
('S1'),
('S2'),
('S3'),
('S4'),
('S5'),
('S6'),
('S7'),
('S8'),
('S9'),
('S10'),
('S11'),
('S12');
WITH CTE AS
(
SELECT Orders,
(ROW_NUMBER() OVER(ORDER BY LEN(Orders)) - 1) / 5 RN
FROM T
)
SELECT STRING_AGG(Orders, ',')
FROM CTE
GROUP BY RN
ORDER BY RN;
OR
SELECT STUFF(
(
SELECT ',' + Orders
FROM CTE
WHERE RN = TT.RN
FOR XML PATH('')
), 1, 1, ''
) Orders
FROM CTE TT
GROUP BY RN
ORDER BY RN;
您可以使用
(SELECT 1)
代替LEN(Orders)
返回:
+-----------------+
| Orders |
+-----------------+
| S1,S2,S3,S4,S5 |
| S6,S7,S8,S9,S10 |
| S11,S12 |
+-----------------+