Question

我有一个正则表达式，用于检查inputText是否为有效的url格式。并且工作得差不多：

checkUrlFormat() {
    const pattern = /^(?:(?:https?|ftp):\/\/)?(?:(?!(?:10|127)(?:\.\d{1,3}){3})(?!(?:169\.254|192\.168)(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]-*)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[a-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/\S*)?$/;

    if (pattern.test(this.inputText) || this.inputText == null) {
      return false;
    }
    return true;
  }

但是我需要缩短模式，所以我在https://www.debuggex.com/#cheatsheet中写了一个正则表达式为

(((http|https)(://))?((www).)?)[a-z0-9]+(.|[a-z0-9])+[a-z0-9]

但是它是javascript格式，我找不到如何在上面的代码中使用该字符串。当我直接复制粘贴它时，它给出了语法错误。我如何将它们结合起来。

Answer 1

checkUrlFormat() {
    const pattern = /^(((http|https)(:\/\/))?((www).)?)[a-z0-9]+(.|[a-z0-9])+[a-z0-9]$/;

    if (pattern.test(this.inputText) || this.inputText == null) {
      return false;
    }
    return true;
  }

将Javascript正则表达式转换为Typescript正则表达式

1 个答案: