Question

我正在尝试制作井字游戏。我进行了此功能，该功能应该更新板的值（插入“ X”或“ O”），但结构只是不更新，它表明这些值与初始化的值相同。

#include <iostream>

struct Board {//initializes a struct
    char A1 = ' ';
    char A2 = ' ';
    char A3 = ' ';
    char B1 = ' ';
    char B2 = ' ';
    char B3 = ' ';
    char C1 = ' ';
    char C2 = ' ';
    char C3 = ' ';
};

struct Board InputSignInStruct(char num, char letter, struct Board b,char sign) {//a function which is supposed to update values in the struct
    if (letter == 'A')
    {
        if (num == '1')
            b.A1 = sign;
        if (num == '2')
            b.A2 = sign;
        if (num == '3')
            b.A3 = sign;
    }
    if (letter == 'B')
    {
        if (num == '1')
            b.B1 = sign;
        if (num == '2')
            b.B2 = sign;
        if (num == '3')
            b.B3 = sign;
    }
    if (letter == 'C')
    {
        if (num == '1')
            b.C1 = sign;
        if (num == '2')
            b.C2 = sign;
        if (num == '3')
            b.C3 = sign;
    }
    return b;
}

int main() {
    struct Board b;
    char letter,num;
    std::cin>>letter>>num;
    char sign;
    std::cin>>sign;
    b = InputSignInStruct(letter, num, b, 'X');//should return the updated struct but it doesent update
}

Answer 1

您的函数定义是

func tableView(_ tableView: UITableView, commit editingStyle: UITableViewCell.EditingStyle, forRowAt indexPath: IndexPath) {
    let keys = firstTbaleViewBoatArray[indexPath.row].key
    DB_BASE.child("boat").child(keys).removeValue { (error, ref) in
        if error != nil {
            print("could not delete")
            return
        } else {
            self.firstTbaleViewBoatArray.remove(at: indexPath.row) //out of range error happened here
            self.tableView1.deleteRows(at: [indexPath], with: .fade)
            self.tableView1.reloadData()

        }
    }
}

但是你打电话给

$doc = new DOMDocument();
$doc->loadXML($xml);

// convert to xpath
$xpath = new DOMXPath($doc);

// search
$search_results = $xpath->query('//flight//hotel[@id=678]');

您已将struct Board InputSignInStruct(char num, char letter, ...)和b = InputSignInStruct(letter, num ...)互换。

Answer 2

您需要使函数调用值与定义匹配。

更改此：

b = InputSignInStruct(letter, num, b, 'X');/

对此：

b = InputSignInStruct(num, letter, b, 'X');/

修改结构的功能不会更新结构

2 个答案: