我想按月找到总和。结果返回0行记录。
Table 1: aidat
1 Messi
2 Ronaldo
3 Neymar
Table 2: aidat_hareket
12 1(messi) 200 12-12-2018
13 3 150 12-11-2018
14 2 25 10-10-2018
15 1 150 10-12-2018
16 3 125 08-05-2018
I want to result this:
id name jan feb march april may ... oct nov dec
1 messi 0 0 0 0 0 0 0 350
2 ronaldo 0 0 0 0 0 25 0 0
3 neymar 0 0 0 0 125 0 150 0
它在mysql中返回了0行。我尝试在内部联接中按month(ah.datee) and a.student_id;
,month(ah.datee), a.student_id;
和a.student_id;
分组。但是结果是一样的。
SELECT o.id as o_id, o.ad, s.ad as s_ad, s.plaka, v.id as veli_id,v.ad as
veli_ad, v.telefon,s.demo,
if(month(ah.datee)=1 , ah.collection,0) as jan,
if(month(ah.datee)=2 , ah.collection,0) as feb,
if(month(ah.datee)=3 , ah.collection,0) as march,
if(month(ah.datee)=4 , ah.collection,0) as april,
if(month(ah.datee)=5 , ah.collection,0) as may,
if(month(ah.datee)=6 , ah.collection,0) as june,
if(month(ah.datee)=7 , ah.collection,0) as july,
if(month(ah.datee)=8 , ah.collection,0) as august,
if(month(ah.datee)=9 , ah.collection,0) as sep,
if(month(ah.datee)=10, ah.collection,0) as oct,
if(month(ah.datee)=11, ah.collection,0) as nov,
if(month(ah.datee)=12, ah.collection,0) as december
from aidat a
inner join (select student_id, sum(collection_tutari) as collection, collection_datee as datee from aidat_hareket )
ah on ah.student_id = a.student_id
inner join student o on o.id = a.student_id
inner join service s on s.id = o.service_id
inner join service_firma sf on sf.id = s.firma_id
left join aile al on al.student_id = a.student_id
left join veli v on v.id = al.veli_id
inner join aylar ay on ay.id = month(ah.datee)
where a.aylik_odeme_tutari != 0 and sf.id = 23
group by month(ah.datee), a.student_id;
我该如何解决?