替换所有行中的值

Question

我在表中有大约50条左右的记录，我需要一个sql语句来更新所有5到9的引用列id。如何将它应用于每个适用的记录？

Answer 1

UPDATE YourTable
SET referral_column_id = 9
WHERE referral_column_id = 5;

Answer 2

UPDATE `table_name` SET `column_id` = 9 WHERE `column_id` = 5;

Answer 3

UPDATE col SET referral = 9 WHERE referral =5