Question

我正在编写此CUDA代码，以使用CUDA将RGB图像转换为灰度。我目前正在学习CUDA和OpenCV，因此大部分内容都是在其他代码（尤其是“并行程序简介”）的帮助下编写的。

我得到的输出是纯灰色图像。如何在此代码中找到问题？

#include <iostream>
#include <cuda.h>
#include <cuda_runtime.h>
#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc.hpp>

using namespace cv;
using namespace std;

__global__ void rgba_to_greyscale(const uchar4* const rgbaImage,
    unsigned char* greyImage,
    int numRows, int numCols)
{
    int col = blockIdx.x * blockDim.x + threadIdx.x;
    int row = blockIdx.y * blockDim.y + threadIdx.y;        

    if (col >= numCols || row >= numRows) {
        return;
}

    int offset = row * numCols + col;

    uchar4 rgba_pixel = rgbaImage[offset];
    float greyness = .299f * rgba_pixel.x + .587f * rgba_pixel.y +
        .114f * rgba_pixel.z;
    greyImage[offset] = static_cast<unsigned char>(greyness);
}

int main()
{
    Mat imageRGBA;
    Mat imageGrey;
    uchar4        *h_rgbaImage;
    uchar4 *d_rgbaImage = NULL;
    unsigned char *h_greyImage;
    unsigned char *d_greyImage = NULL;
    ///////////////////////////////////
    Mat image;
    image = cv::imread("IMG.jpg");
    if (image.empty()) {
        cerr << "Couldn't open file: " << endl;
        exit(1);
    }

    ///////////////////////////////////
    int numRows = image.rows;
    int numCols = image.cols;
    ///////////////////////////////////////
    cvtColor(image, imageRGBA, COLOR_BGR2RGBA);    

    //Allocate Memory for output
    imageGrey.create(image.rows, image.cols, CV_8UC1);
    h_rgbaImage = (uchar4 *)imageRGBA.data;
    h_greyImage = (unsigned char *)imageGrey.data;

    const size_t numPixels = numRows * numCols;

    //Allocate memory on the device for both input and output

    cudaMalloc((void**)d_rgbaImage, sizeof(uchar4) * numPixels);
    cudaMalloc((void**)d_greyImage, sizeof(unsigned char) * numPixels);
    cudaMemset((void *)d_greyImage, 0, numPixels * sizeof(unsigned char));
    //Copy input array to the GPU

    cudaMemcpy(d_rgbaImage, h_rgbaImage, sizeof(uchar4)*numPixels,         
    cudaMemcpyHostToDevice);

    //Calling the Kernel - 

    const dim3 blockSize(32, 16, 1);
    const dim3 gridSize(1 + (numCols / blockSize.x), 1 + (numRows /     
     blockSize.y), 1);

    rgba_to_greyscale <<<gridSize, blockSize >>> (d_rgbaImage, d_greyImage, 
    numRows, numCols);

    //Copy Output array to Host

    cudaMemcpy(h_greyImage, d_greyImage, sizeof(unsigned char) * numPixels,     
    cudaMemcpyDeviceToHost);

    //Check Output
    Mat output;
    output = Mat(numRows, numCols, CV_8UC1, (void*)h_greyImage);
    imwrite("result.jpg", output);  
}

Answer 1

代码中的设备内存分配调用无效。

cudaMalloc((void**)d_rgbaImage, sizeof(uchar4) * numPixels);
cudaMalloc((void**)d_greyImage, sizeof(unsigned char) * numPixels);

实际上，以上调用无济于事。请按照以下说明更正调用，以便实际修改指针。

cudaMalloc((void**)&d_rgbaImage, sizeof(uchar4) * numPixels);
                   ^
cudaMalloc((void**)&d_greyImage, sizeof(unsigned char) * numPixels);
                   ^

此外，请确保您在代码中check for CUDA errors，以便可以轻松跟踪此类问题。

如何查找为什么CUDA / OpenCV程序返回纯灰色图像？

1 个答案: