我有一个数组:
wireholder.wires[]
此数组包含每次迭代中带有tr
子项的HTML td
元素:
wireholder.wires[1] =
<tr class="trClass" id="blah">
<td class="tdClass0">
<select class="selectClass">
<option value="1">Option1</option>
<option value="2">Option2</option>
<option value="3">Option3</option>
</select>
</td>
<td class="tdClass1">
<input class="inputClass1" type="text" />
</td>
<td class="tdClass2">
<input class="inputClass2" type="text" />
</td>
</tr>
我希望能够在此数组迭代中定位类名。
$(wireholder.wires[i].classNameHere)
之类的东西正是我所追求的。
有没有人听说有什么方法可以做这样的事情?
for(i=0;i<oldElement.length;i++){
if($(node).find('.wire_selector_' + row).length){
var oldWire = $(node).find('.wire_selector_' + row).val();
}
if($(node).find('.wire_length_' + row).length){
var oldLength = $(node).find('.wire_length_' + row).val();
}
if($(node).find('.wire_retail_' + row).length){
var oldPrice = $(node).find('.wire_retail_' + row).val()*100;
}
}
function DomFactory()
{
this.buildElement = function(elementType, props) {
var el = document.createElement(elementType);
for (var prop in props) {
el.setAttribute(prop, props[prop]);
}
return el;
};
this.buildTextNode = function(nodeData) {
var node = document.createTextNode(nodeData);
return node;
};
}
然后使用DomFactory:
var dom_builder = new DomFactory();
var part_stub = dom_builder.buildElement("tr", {'class': "wiring_details_" + Wireholder.wires.length + "-" + part_id + "-" + zone_id, 'id': "wiring_rows_" + Wireholder.wires.length});
var part_td = dom_builder.buildElement("td", {'colspan': '2'});
var wire_type = dom_builder.buildTextNode("Wire Type: ");
var select_wire = dom_builder.buildElement("select", {'class': 'wire_selector_' + Wireholder.wires.length, 'name': 'select_wire_' + Wireholder.wires.length});
var wireValues = ["Select wire..", "14/2", "14/4", "16/4", "16/2", "RG6", "CAT5", "RG59", "LVT", "CAT6", "HDMI", "Shielded CAT6"];
var length_stub = dom_builder.buildElement("td", {'colspan': '2'});
var wire_length = dom_builder.buildTextNode("Length: ");
var wire_length_input = dom_builder.buildElement("input", {'type': "text", 'class': 'wire_length_' + Wireholder.wires.length, 'name': 'wire_length_' + Wireholder.wires.length, 'value': '1'});
var retail_stub = dom_builder.buildElement("td", {'colspan': '2'});
var wire_retail_price = dom_builder.buildTextNode("Retail Price: ");
var wire_retail_input = dom_builder.buildElement("input", {'type': "text", 'class': 'wire_retail_' + Wireholder.wires.length, 'name': 'wire_retail_' + Wireholder.wires.length, 'value': '0'});
var total_stub = dom_builder.buildElement("td", {'colspan': '2', 'class': "wire_total"});
var add_button = dom_builder.buildElement("a", {'href': "#", 'class': "add-button", 'id': "wiring_button_" + Wireholder.wires.length});
var add_wire = dom_builder.buildTextNode("Add Wire");
var wire_id = dom_builder.buildElement("input", {'type': "hidden", 'id': 'wire_id_<?php echo $part->id; ?>', 'name': 'wire_id_<?php echo $part->id; ?>', 'value': '<?php echo $part->wire_id; ?>'});
that.appendChild(part_stub);
Wireholder.wires.push(part_stub);
还有更多,但你明白了......
答案 0 :(得分:4)
试试这个:
$(wireholder.wires[1]).find(".tdClass1")
通过用$()
包装它,你可以将它变成jQuery“集合”,可以搜索特定的类等。