Question

我正在尝试使用JavaScript中的子类，并且正在使用Marvel电影来做到这一点。这是我的超类：

class Episode {
  constructor(title, releaseDate, storyYear, phase, order, runtime, hero){
    this.title = title;
    this.releaseDate = releaseDate;
    this.releaseMonth = parseInt(releaseDate.split('/')[0]);
    this.releaseYear = parseInt(releaseDate.split('/')[1]);
    this.episodeType = "";
    this.storyYear = storyYear;
    this.phase = phase;
    this.order = order;
    this.runtime = runtime;
    this.hours = parseInt(runtime.split(':')[0]);
    this.minutes = parseInt(runtime.split(':')[1]);
    this.hero = hero;
  }
}

现在，我创建了3个子类。一种用于电影，一种用于电视节目，一种用于“一枪”。通过这种方式，我可以添加更多信息，例如电视季，剧集以及一张照片属于哪个DVD。

  class Movie extends Episode {
    constructor(title, releaseYear, storyYear, phase, order, runtime, hero){
      super(title, releaseYear, storyYear, phase, order, runtime, hero);
      this.episodeType = "Movie";
    }
  }
  class TVShow extends Episode {
    constructor(title, releaseYear, storyYear, phase, order, runtime, hero, episode){
      super(title, releaseYear, storyYear, phase, order, runtime, hero);
      this.episodeType = "TV Show";
      this.episode = episode;
    }
  }
  class OneShot extends Episode {
    constructor(title, releaseYear, storyYear, phase, order, runtime, hero){
      super(title, releaseYear, storyYear, phase, order, runtime, hero);
      this.episodeType = "One Shot";
    }
  }

我看到的问题是，如果我必须将构造函数添加到原始情节中，还必须将其也添加到每个子类中。这是最有效的方法吗？

Answer 1

如@Bergi所建议的那样，您可以使用参数列表，而不是显式定义每个参数，例如

Array
(
    [aoepeople/scheduler] => v1.6.13
    [nwdthemes/revslider] => dev-master
    [churiart/blogomatic] => dev-master
    [php-pm/php-pm] => v1.0.4
    .
    .
    .

这样，您可以获得更简洁的代码，并避免在所有地方列出所有参数。但是，您将丢失所有参数的隐式定义，并且可能希望手动实现一些约束。例如如果class Episode{ constructor(args) { this.args = args; } } class Movie extends Episode{ constructor(args){ args.episodeType = 'Movie'; super(args); } } // The same for all subclasses未定义或为空，则会引发错误。

有没有办法清理javascript中的子类参数？

1 个答案: