我创建了QInputDialog并在其中配置了事件过滤器,但是我不知道如何防止在eventFilter(self, widget, event)
方法中单击ESC或ENTER按钮时关闭它。
self.inDialog = QInputDialog(self)
#some config...
self.inDialog.setLabelText('')
self.nameAction.setText('&Nazwa pola głównego ✔')
self.inDialog.show()
我的事件过滤器概念:
def eventFilter(self, widget, event):
if isinstance(event, QtGui.QKeyEvent):
if event.key() == 16777220:
return False
# here I want to call super somehow?
return
值得一提的是,我正在QMainWindow类中执行所有这些操作,从中我将其称为QInputdialog。我宁愿不要继承QDialog并手动编写所有内容。
答案 0 :(得分:1)
如果要避免事件QInputDialog
发生,则必须在过滤器中返回True
,另一方面,最好使用Qt::Key
进行可读的代码。
from PyQt5 import QtCore, QtGui, QtWidgets
class MainWindow(QtWidgets.QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
button = QtWidgets.QPushButton("Press me")
button.clicked.connect(self.opendialog)
self.setCentralWidget(button)
self.inDialog = QtWidgets.QInputDialog()
self.inDialog.setLabelText('')
self.inDialog.installEventFilter(self)
@QtCore.pyqtSlot()
def opendialog(self):
if self.inDialog.exec_() == QtWidgets.QDialog.Accepted:
print("Acepted")
print(self.inDialog.textValue())
def eventFilter(self, obj, event):
if obj is self.inDialog and event.type() == QtCore.QEvent.KeyPress:
if event.key() in (QtCore.Qt.Key_Return,
QtCore.Qt.Key_Escape,
QtCore.Qt.Key_Enter,):
return True
return super(MainWindow, self).eventFilter(obj, event)
if __name__ == '__main__':
import sys
app = QtWidgets.QApplication(sys.argv)
w = MainWindow()
w.show()
sys.exit(app.exec_())
更新:+禁用关闭按钮:
def eventFilter(self, obj, event):
if obj is self.inDialog:
if event.type() == QtCore.QEvent.KeyPress:
if event.key() in (QtCore.Qt.Key_Return,
QtCore.Qt.Key_Escape,
QtCore.Qt.Key_Enter,):
return True
if event.type() == QtCore.QEvent.Close:
event.ignore()
return True
return super(MainWindow, self).eventFilter(obj, event)