如何使用Alamofire和OAuth1验证URLRequest

Question

我在尝试使用alamofire和OAuth1对请求进行身份验证时遇到问题，并且正在使用此库来这样做： https://github.com/phenemann/Authentication/ 但是如果您知道如何将Alamofire与OAuth1结合使用，我将无法成功。

宝贝，直到现在我的进步

class HttpRestManager{
public static func sendRequest(url: String, authorizationType: AuthorizationType, method: HTTPMethod, parameters: [String: Any]?, headers: NSMutableDictionary, complition: @escaping (_ results: String?, _ errors: Error?, _ statusCode: Int?) -> Void){
    let preparedHeaders = prepareHeaders(headers: headers, authorizationType: authorizationType)
    let manager = Alamofire.SessionManager.default
    manager.session.configuration.timeoutIntervalForRequest = 10
    manager.adapter = AuthorizationAdapter()
    manager.request(url, method: method, parameters: parameters, encoding: JSONEncoding.default, headers: preparedHeaders).responseString { (response) in
        switch response.result{
        case .success(let value):
            complition(value, nil, response.response?.statusCode)
        case .failure(let error):
            complition(nil, error, response.response?.statusCode)
        }
    }
}
}

这是我正在使用的适配器：

class AuthorizationAdapter: RequestAdapter {
private let CONSUMER_KEY = "****";
private let CONSUMER_SECRET = "****";
private let TOKEN_ID = "****";
private let TOKEN_SECRET = "****";

func adapt(_ urlRequest: URLRequest) throws -> URLRequest {
    let oAuthMethod = AuthenticationMethod.oauth1(consumerKey: CONSUMER_KEY,
                                                  consumerSecret: CONSUMER_SECRET,
                                                  accessKey: TOKEN_ID,
                                                  accessSecret: TOKEN_SECRET)
    let authorizer = Authenticator(method: oAuthMethod)
    let authorizedRequest = try? authorizer.signRequest(request: urlRequest)
    return authorizedRequest!
}
}

请注意，我有ConsumerKey，ConsumerSecret，TokenID和TokenSecret，没有CallBackUrl或我只需要根据请求URL及其参数生成“ oauth_signiture”值，就已经生成了，但是响应我得到的是“ INVALID_LOGIN_ATTEMPT”，每当我在Postman上测试API时，即使生成的标头类似于我生成的标头，它也会成功，请帮助我或告诉我我做错了，非常感谢。