Question

我有一个csv文件，如下所示：

No                    String

1                     A B A A B C D E E C F

1                     B B B C M F G

1                     A A M V 

2                     H C A A A B B N M F 

2                     N M H D D B A F F N M N

3                     A C M G F F A A A

..                    ....

我想将此文件转换为包含节点的图：A，B，C，D，E，F，G，H，M，N，V，它们之间的边是“否”列中的值考虑循环。

任何提示将不胜感激。

Answer 1

我刚刚在浏览过程中看到了您的问题，但是可能有所延迟，但可能有帮助首先创建一个有向图和一个列表图= DiGraph（） string_list = list＃添加所有字符串

因此，首先您必须读取文件并将其放入您喜欢的任何数据结构中。在这种情况下，我将其放入字典

with open(file_path, 'r', encoding='utf-8') as csvfile:
    reader = DictReader(csvfile)
    data = [dict(x) for x in reader]

之后

    for row in data: # for each item in the dictionary 
        string_list.extend(row['String'].split(' ')) # add a list of strings which are separated by "space" into a list. So that, you can access each character
         for char in string_list: # for each element in the list (each character)
            Graph.add_edge(row['No'], char) (create an edge between each "No" with each character )

print(Graph.edges())

这应该有效

从Python中的字符串构建图形

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