Question

我有一个简单的spring boot REST应用程序。这是DTO的样子：

@Data
public class FooDto {
@Min(value = 0L)
@NotNull
private final String amount;

@ValidTimestamp
private final String timestamp;
}

我在@ValidTimestamp中提供了一些验证逻辑，用于检查时间戳格式是否有效。但是问题是，我在此处加上@ValidTimestamp注释的时刻，整个DTO中的所有其他默认JSR验证都停止工作。他们根本不开火。如果我注释掉@ValidTimestamp，则那些默认的JSR验证将变为活动状态。我在整个互联网上查找，但找不到任何解决方案。欣赏快速指针。

这是验证器类：

public class TimestampValidator implements ConstraintValidator<ValidTimestamp, String> {

@Override
public void initialize(@NonNull final ValidTimestamp constraintAnnotation) {
    constraintAnnotation.payload();
}

@Override
public boolean isValid(final String timestamp,
                       @NonNull final ConstraintValidatorContext constraintValidatorContext) {
    try {

        final Duration duration = Duration.between(Instant.parse(timestamp), Instant.now());
        throwIfOldTimeStampProvided(duration);
        throwIfFutureTimestampProvided(duration);
    } catch (DateTimeParseException dateTimeParseException) {
        return throwInvalidTimestampFormatException(dateTimeParseException);
    }
    return true;
}

private boolean throwInvalidTimestampFormatException(@NonNull final DateTimeParseException dateTimeParseException) {
    log.error("failed to parse the timestamp, exception is : {}", dateTimeParseException);
    throw new InvalidTimestampFormatException("invalid timestamp supplied via request");
}

private void throwIfOldTimeStampProvided(@NonNull final Duration duration) {
    if (duration.toMillis() > ACTIVE_TRANSACTION_TIME_REFERENCE * 1000) {
        throw new StaleTransactionException("Transaction time is  more than a minute ago");
    }
}

private void throwIfFutureTimestampProvided(@NonNull final Duration duration) {
    if (duration.isNegative()) {
        throw new FutureTransactionException("Transaction time is of future");
    }
}
}

这是注释：

@Target({FIELD})
@Retention(RUNTIME)
@Constraint(validatedBy = {TimestampValidator.class})
public @interface ValidTimestamp {
    String message() default "";

    Class<?>[] groups() default {};

    Class<? extends Payload>[] payload() default {};
}

JSR验证不适用于定制验证器弹簧启动

0 个答案: