Question

因此，我正忙于制作一个基于文本的交互式游戏，用户可以用自己的单词输入答案。

我写了一段代码来在用户输入某些单词时打印某些字符串，但我无法使其正常工作。

无论我输入什么，它总是打印“ NOVA ENTER THE SPACECRAFT” 我在做什么错了？

下面是我的代码段：

craft_cave = input(char_name + ": I should probably search the ship for supplies and explore this cave, which should I do first? ")

print("")

if "craft" or "Craft" or "ship" or "Ship" in craft_cave:
  print("NOVA ENTERS THE SPACECRAFT")
elif "cave" or "Cave" or "mountain" or "Mountain" in craft_cave:
  print("NOVA LOOKS AROUND THE CAVE")
else:
  print("Invalid answer")

Answer 1

您需要逐字检查单词。尝试类似的东西：

vehicle_words = ["craft", "Craft", "ship", "Ship"]
cave_words = ["cave", "Cave", "mountain", "Mountain"]
if any(w in craft_cave for w in vehicle_words):
    print("NOVA ENTERS THE SPACESHIP")
elif any(w in craft_cave for w in cave_words)
    print("NOVA LOOKS AROUND THE CAVE")
else:
    print("Invalid Answer")

Answer 2

条件错误，它将检查"craft"的值是否正确。您应该执行以下操作：

if "craft" in craft_cave or "Craft" in craft_cave or "ship" in craft_cave or "Ship" in craft_cave:
    # continue

更好：

if any(map(lambda word: word in craft_cave, ("craft", "Craft", "ship", "Ship"))):
    # continue

Answer 3

if "craft" or "Craft" or "ship" or "Ship" in craft_cave:

被评估为

if ("craft" or ("Craft" or ("ship" or ("Ship" in craft_cave) ) ) ):

"craft"首先被评估为布尔值，从而得到True，所以我们有

if (True or ("Craft" or ("ship" or ("Ship" in craft_cave) ) ) ):

并且由于True or x始终为True，因此该语句的计算结果为

if True:

因此第一个if条件始终求值为True。

您需要直接检查每个if条件中的每个单词

spacecraft_keywords = ["craft", "Craft", "ship", "Ship"]
cave_keywords = ["cave", "Cave", "mountain", "Mountain"]

def contains_any(keywords, s):
    return any(keyword in s for keyword in keywords)

if contains_any(spacecraft_keywords, craft_cave):
    pass
elif contains_any(cave_keywords, craft_cave):
...

Answer 4

一种简单的方法，将所有单词都放在列表中

craft_cave = input( ": I should probably search the ship for supplies and explore 
this cave, which should I do first? ")

print("")
list1 = ('craft', 'Craft', 'ship', 'Ship')
list2 = ('cave', 'Cave', 'mountain', 'Mountain')  

if any(word in craft_cave for word in list1):
   print("NOVA ENTERS THE SPACECRAFT")

elif any(word in craft_cave for word in list2):
   print("NOVA LOOKS AROUND THE CAVE")

else:
   print("invalid")

检查一个字符串是否在python中包含另一个字符串

4 个答案: