我收到错误:尝试检索JSON值时,org.json.JSONObject类型无法转换为JSONArray。
JSONArray jsonarray = new JSONArray(data);
for(int i = 0; i < jsonarray.length(); i++){
JSONObject JO = (JSONObject) jsonarray.get(i);
String id = JO.getString("languages");
dataParsed = dataParsed + id;
}
JSON如下所示(已删除敏感数据)
{
"ip":"",
"type":"",
"continent_code":"EU",
"continent_name":"Europe",
"country_code":"GB",
"country_name":"United Kingdom",
"region_code":"ENG",
"region_name":"England",
"city":"",
"zip":"",
"latitude":,
"longitude":,
"location":{
"geoname_id":,
"capital":"London",
"languages":[
{
"code":"en",
"name":"English",
"native":"English"
}
],
"country_flag":"http:\/\/assets.ipstack.com\/flags\/gb.svg",
"country_flag_emoji":"\ud83c\uddec\ud83c\udde7",
"country_flag_emoji_unicode":"U+1F1EC U+1F1E7",
"calling_code":"44",
"is_eu":true
}
}
我应该提到我实际上想要检索的数据是语言的名称。
答案 0 :(得分:0)
您可以尝试以下方法:
JSONObject obj = new JSONObject(data);
JSONObject objLocation = obj.getJSONObject("location");
JSONArray arrayLanguage = objLocation.getJSONArray("languages");
for (int i = 0; i < arrayLanguage.length(); i++) {
JSONObject JO = (JSONObject) arrayLanguage.get(i);
String id = JO.getString("languages");
dataParsed = dataParsed + id;
}