我有一组rect,它们连续显示。我希望他们在单击它们后更改其颜色,直到再次单击它们
到目前为止,我已经有了以下代码来创建精灵:
class DrawableRect(pygame.sprite.Sprite):
def __init__(self,color,width,height,value=0):
super().__init__()
self.image = pygame.Surface([width, height])
self.image.fill(color)
self.rect = self.image.get_rect()
self.value = value
self.x = 0
self.y = 0
def change_value(self,color,value):
self.image.fill(color)
self.value=value
def DrawRects(start_x, start_y, rect_spacing, colour_list):
current_x_pos = start_x
for rect_num in range(0,8):
rect = DrawableRect(colour_list[rect_num], boxW, boxH)
rect.rect.x = current_x_pos
rect.rect.y = start_y
current_x_pos = current_x_pos + rect.rect.width + rect_spacing
rects.add(rect)
rects.draw(screen)
该应用的想法是让每个矩形代表一个位,当按下它时,它会在0和1之间交替显示,每个位的组成都会在某处显示等效的十进制数。
我读到组是无序的,因此无法建立索引,对吗?
答案 0 :(得分:1)
这是我为适应您的目的而修改的示例。我在一个精灵群组中有一堆精灵(彩色矩形),并且我改变了*按下鼠标按钮时碰撞的任何精灵的颜色。
这是代码,您可能对change_color()
方法和MOUSEBUTTONUP
事件处理代码最感兴趣。
import random
import pygame
screen_width, screen_height = 640, 480
def get_random_position():
"""return a random (x,y) position in the screen"""
return (random.randint(0, screen_width - 1), #randint includes both endpoints.
random.randint(0, screen_height - 1))
color_list = ["red", "orange", "yellow", "green", "cyan", "blue", "blueviolet"]
colors = [pygame.color.Color(c) for c in color_list]
class PowerUp(pygame.sprite.Sprite):
def __init__(self):
pygame.sprite.Sprite.__init__(self)
width, height = 64, 32
self.image = pygame.Surface([width, height])
self.clicked = False # track whether we've been clicked or not
# initialise color
self.color = random.choice(colors)
self.image.fill(self.color)
# Fetch the rectangle object that has the dimensions of the image
self.rect = self.image.get_rect()
# then move to a random position
self.update()
def update(self):
#move to a random position
self.rect.center = get_random_position()
def random_color(self):
# randomise color
self.clicked = not self.clicked
if self.clicked:
color = random.choice(colors)
else:
color = self.color
self.image.fill(color)
if __name__ == "__main__":
pygame.init()
screen = pygame.display.set_mode((screen_width, screen_height))
pygame.display.set_caption('Sprite Color Switch Demo')
clock = pygame.time.Clock() #for limiting FPS
FPS = 60
exit_demo = False
pygame.key.set_repeat(300, 200)
#create a sprite group to track the power ups.
power_ups = pygame.sprite.Group()
for _ in range(10):
power_ups.add(PowerUp()) # create a new power up and add it to the group.
# main loop
while not exit_demo:
for event in pygame.event.get():
if event.type == pygame.QUIT:
exit_demo = True
elif event.type == pygame.KEYDOWN:
if event.key == pygame.K_ESCAPE:
exit_demo = True
elif event.key == pygame.K_SPACE:
power_ups.update()
elif event.type == pygame.MOUSEBUTTONUP:
# check for collision
for p in power_ups:
if p.rect.collidepoint(event.pos): # maybe use event?
p.random_color()
screen.fill(pygame.Color("black")) # use black background
power_ups.draw(screen)
pygame.display.update()
clock.tick(FPS)
pygame.quit()
quit()
如果您有任何疑问,请告诉我。显然,这不会对sprite进行行对齐,我认为您对此有一个了解。我建议您将所有屏幕绘制操作都放在一个位置,以便代码更清晰。
*新颜色是从短列表中随机分配的,因此它有14%的可能性不会与初始颜色保持不变。