Question

我有以下查询：

SELECT
    INIZIO.idinizio AS id,
    inizio,
    fine,
    barca
FROM
    (
        (
        SELECT
            ID AS idinizio ,
            meta_value AS inizio,
            term_taxonomy_id AS barca
        FROM
            wp_posts
        INNER JOIN wp_postmeta ON(
                ID = post_id AND post_type = 'tribe_events' AND meta_key = '_EventStartDate' AND(
                    post_status = 'publish' OR post_status = 'private'
                )
            )
        INNER JOIN wp_term_relationships ON(
                ID = object_id
            )
        ) AS INIZIO
INNER JOIN
        (
        SELECT
            ID AS idfine,
            meta_value AS fine
        FROM
            wp_posts
        INNER JOIN wp_postmeta ON(
                ID = post_id AND post_type = 'tribe_events' AND meta_key = '_EventEndDate' AND(
                    post_status = 'publish' OR post_status = 'private'
                )
            )
        ) AS FINE
ON (idinizio = idfine)
)

当我运行它时，出现以下错误：

Error Code: 1054. Unknown column 'idinizio' in 'field list'

Image of my table

为什么会出现此错误？

在子查询或某些表别名中肯定会是初学者的错误。

更新：

..现在我意识到我已经颠倒了所有的AS子句.. 我已修复，现在给我这个错误：

#1054 - Colonna sconosciuta 'posts.idinizio' in 'on clause'

更新：我把表前缀弄错了，我把它改正了，现在一切正常，非常感谢你让我注意到错误！

Answer 1

您应该在底部将idinizio列替换为ID，将ON (INIZIO.ID = FINE.idfine)列替换为ID，因为在上面的内部查询中，该列已被别名为IntList password = new IntList(14, 2, 12); IntList attempt = new IntList(); boolean isLoggedIn = true; attempt.append(14); attempt.append(2); attempt.append(12); for (int i = 0; i < attempt.size(); i++) { if (password.get(i) != attempt.get(i)) { isLoggedIn=false; } } if (isLoggedIn) { println("You are logged in"); } else { println("Password incorrect"); }。

当然这是一个愚蠢的语法错误，但我是sql的初学者：1054。未知列错误

1 个答案: