Question

我在 JObject 中添加了一个新孩子。可行。

var fi = e.PropertyA;
JObject o = JObject.FromObject(fi);
o.AddFirst(new JProperty("type", new JValue(fi.GetType().Name)));

// this works
o.Add("description", new JObject( new JProperty("de", new JValue("Wert"))));
var node = o.SelectToken("description");

if (node != null)
{
  // this fails
  // node.AddAfterSelf(new JProperty("en", "Value"));
}

"PropertyA": {
    "type": "SubObject",
    "Foo": "foo",
    "description": {
      "de": "Wert"
  }
}

之后，我尝试将一个新对象添加到之前创建的令牌中。失败并显示以下错误消息：

Newtonsoft.Json.JsonException：Newtonsoft.Json.Linq.JProperty不能有多个值

要重现该错误行为，请删除此fiddle中的注释。

我需要的是这样的国际化JSON对象。

一个客户希望获得英语信息

{
  "venue_id": "C001",
  "venue_location": "Baker St."
  "venue_name": "Aroma Coffee"
}

另一个客户希望以希伯来语获取信息

{
  "venue_id": "C001",
  "venue_location": "רחוב האופה"
  "venue_name": "קפה ארומה"
}

结果应该像这样

{
  "venue_id": "C001",
  "venue_location": {
    "en": "Baker St.",
    "he": "רחוב האופה"
  }
  "venue_name": {
    "en": "Aroma Coffee",
    "he": "קפה ארומה"
  }
}

在Approaches to JSON internationalisation (i18n)中描述

Answer 1

因此有效

o.Add("description", new JObject( new JProperty("de", new JValue("Wert"))));
var node = o.SelectToken("description") as JObject;
if (node != null)
{
    node.Add(new JProperty("en", "Value"));
}

产生

"PropertyA": {
    "type": "SubObject",
    "Foo": "foo",
    "description": {
      "de": "Wert",
      "en": "Value"
    }
}

@ er-shoaib：感谢您的努力

尝试将特定内容添加到令牌中将返回“ Newtonsoft.Json.Linq.JProperty不能具有多个值。”

1 个答案: