Question

我正在尝试将vars绑定到我的原始查询中，

$query = "SELECT 1 AS rank, 'CATEGORY' AS type, category_id AS id, name AS name
          FROM category_translations
          JOIN categories ON categories.id = category_translations.category_id
          WHERE name LIKE '%?%'";

$results = DB::select($query, ['ger']);

但是我无法这样做。我尝试通过绑定命名的参数，也尝试在DB::raw内使用DB::select而不成功。

我在这里做什么错了？

Answer 1

尝试那样使用

$query = "SELECT 1 AS rank, 'CATEGORY' AS type, category_id AS id, name AS name
          FROM category_translations
          JOIN categories ON categories.id = category_translations.category_id
          WHERE name LIKE '% :nameSearch %'";

$results = DB::select(DB::raw($query), ['nameSearch' => 'ger']);

第二种用法

$searchText = "ger";
$results = DB::select(DB::raw($query), ['nameSearch' => "%".$searchText."%"]);

Answer 2

您需要将%添加到绑定值中，而不要添加到查询中（除非您concat()值）...

$query = "SELECT 1 AS rank, 'CATEGORY' AS type, category_id AS id, name AS name
          FROM category_translations
          JOIN categories ON categories.id = category_translations.category_id
          WHERE name LIKE ?";

$results = DB::select($query, ['%ger%']);

无法在Laravel原始查询中绑定参数

2 个答案: