Question

我有以下几种价格

$rates = array(
    0  => 200,
    1  => 150,
    2  => 150,
    3  => 220,
    4  => 300,
    5  => 310,
    6  => 350,
    7  => 325,
    8  => 325,
    9 => 325,
    10 => 300,
);

因此，必须采用以下格式进行格式化：将今天的日期作为第一个日期，并将以下start_date，finish_date，rate添加到assoc数组中，如果有两个或多个连续的日期，则将其推入相同的索引中，但将日期设为finsih汇率将取决于多少天才结束，这是汇率应如何变化的一个示例。

$new_rates = array (
    'start_date' => '2018-12-07'
    'finish_date' => '2018-12-07'
    'rate' => '200',
    'start_date' => '2018-12-08'
    'finish_date' => '2018-12-09'
    'rate' => '150',
    'start_date' => '2018-12-10'
    'finish_date' => '2018-12-10'
    'rate' => '220',
    'start_date' => '2018-12-11'
    'finish_date' => '2018-12-11'
    'rate' => '300',
    'start_date' => '2018-12-12'
    'finish_date' => '2018-12-12'
    'rate' => '310',
    'start_date' => '2018-12-13'
    'finish_date' => '2018-12-13'
    'rate' => '350',
    'start_date' => '2018-12-14'
    'finish_date' => '2018-12-15'
    'rate' => '325',
    'start_date' => '2018-12-16'
    'finish_date' => '2018-12-16'
    'rate' => '300',
);

如您所见，第一个起始日期可以在今天的日期等开始。任何帮助将不胜感激，谢谢。

Answer 1

您期望的数组有问题。

'start_date' => '2018-12-07'
'finsih_date' => '2018-12-07'
'rate' => '200',

'start_date' => '2018-12-08'
'finsih_date' => '2018-12-09'
'rate' => '150',

您正在重复键start_date，finish_date，rate。因此，如果您尝试分配新的开始日期，则它将覆盖先前的开始日期。（assoc_array是PHP中的哈希表）

我建议您改用这种结构，

$new_rates = [

   [
     'start_date' => '2018-12-07'
     'finsih_date' => '2018-12-07'
     'rate' => '200',
   ],

    [
    'start_date' => '2018-12-08'
    'finsih_date' => '2018-12-09'
    'rate' => '150',
   ]

]

或

$new_rates = [

   200 => [
     'start_date' => '2018-12-07'
     'finsih_date' => '2018-12-07'
   ],

    150 =>[
    'start_date' => '2018-12-08'
    'finsih_date' => '2018-12-09'
   ]

]

Answer 2

好吧，以为我明白您要完成的工作，希望对您有所帮助-您可能希望针对特定用例对代码进行一些清理/整理，但是可以完成工作。

<?php
$rates = array(200, 150, 150, 220, 300, 310, 350, 325, 325, 325, 300);

$count = count($rates);
$previousRate = null; // check for duplicate rates
$uniqueRates = []; // store for unique rates
$duplicateRates = []; // store for duplicate rates
$duplicateCount = 0;
/* fill the stores with uniqueRates and duplicateRates */
for ($i = 0; $i < $count; $i++) {
    $currentRate = $rates[$i]; // take rate
    if($currentRate !== $previousRate) { // not a duplicate rate
        $duplicateCount = 0;
        $uniqueRates[]=$currentRate;
        $previousRate = $rates[$i]; // duplicate check store
    } else { // duplicate rate
        $duplicateCount++;
        $duplicateRates[$currentRate] = $duplicateCount; // store duplicate rate
        continue;
    }
}

$counter = 0;
foreach($uniqueRates as $key => $rate) {
    $dateUnique = date("Y-m-d",
        mktime(null, null, null,
            date("m"), date("d") + $counter, date("Y")));
    if(!key_exists($rate, $duplicateRates)) { // not a duplicate rate
        $newArr[$counter]['start_date'] = $dateUnique;
        $newArr[$counter]['end_date'] = $dateUnique;
        $newArr[$counter]['rate'] = $rate;
    } else { // duplicate rate
        $dateDuplicate = date("Y-m-d",
            mktime(null, null, null,
                date("m"), date("d") + $counter + 1, date("Y")));
        $newArr[$counter]['start_date'] = $dateUnique;
        $newArr[$counter]['end_date'] = $dateDuplicate; // adjusted date for duplicate rates
        $newArr[$counter]['rate'] = $rate;
        $counter++;
    }
    $counter++;
}

echo '<pre>';
var_dump($newArr);
echo '</pre>';

输出：

array (size=8)
  0 => 
    array (size=3)
      'start_date' => string '2018-12-08' (length=10)
      'end_date' => string '2018-12-08' (length=10)
      'rate' => int 200
  1 => 
    array (size=3)
      'start_date' => string '2018-12-09' (length=10)
      'end_date' => string '2018-12-10' (length=10)
      'rate' => int 150
  3 => 
    array (size=3)
      'start_date' => string '2018-12-11' (length=10)
      'end_date' => string '2018-12-11' (length=10)
      'rate' => int 220
  4 => 
    array (size=3)
      'start_date' => string '2018-12-12' (length=10)
      'end_date' => string '2018-12-12' (length=10)
      'rate' => int 300
  5 => 
    array (size=3)
      'start_date' => string '2018-12-13' (length=10)
      'end_date' => string '2018-12-13' (length=10)
      'rate' => int 310
  6 => 
    array (size=3)
      'start_date' => string '2018-12-14' (length=10)
      'end_date' => string '2018-12-14' (length=10)
      'rate' => int 350
  7 => 
    array (size=3)
      'start_date' => string '2018-12-15' (length=10)
      'end_date' => string '2018-12-16' (length=10)
      'rate' => int 325
  9 => 
    array (size=3)
      'start_date' => string '2018-12-17' (length=10)
      'end_date' => string '2018-12-17' (length=10)
      'rate' => int 300

将数组排序为assoc数组，但以相同的速率添加连续的日期

2 个答案: