我正在尝试录制音频文件并使用提取发送它。以下是我用来记录的代码,但我不知道如何发送文件。
正在使用浏览器来记录文件,所以react-native-web。
/* eslint-env browser */
import React from 'react';
const audioType = 'audio/*';
class RecordingAPI extends React.Component {
constructor(props) {
super(props);
this.state = {
recording: false,
audios: [],
};
}
async componentDidMount() {
const stream = await navigator.mediaDevices.getUserMedia({audio: true});
// show it to user
this.audio.src = window.URL.createObjectURL(stream);
this.audio.play();
// init recording
this.mediaRecorder = new MediaRecorder(stream);
// init data storage for video chunks
this.chunks = [];
// listen for data from media recorder
this.mediaRecorder.ondataavailable = e => {
if (e.data && e.data.size > 0) {
this.chunks.push(e.data);
}
};
}
startRecording(e) {
e.preventDefault();
// wipe old data chunks
this.chunks = [];
// start recorder with 10ms buffer
this.mediaRecorder.start(10);
// say that we're recording
this.setState({recording: true});
}
stopRecording(e) {
e.preventDefault();
// stop the recorder
this.mediaRecorder.stop();
// say that we're not recording
this.setState({recording: false});
// save the video to memory
this.saveAudio();
}
saveAudio() {
// convert saved chunks to blob
const blob = new Blob(this.chunks, {type: audioType});
// generate video url from blob
const audioURL = window.URL.createObjectURL(blob);
// append videoURL to list of saved videos for rendering
const audios = this.state.audios.concat([audioURL]);
this.setState({audios});
}
deleteAudio(audioURL) {
// filter out current videoURL from the list of saved videos
const audios = this.state.audios.filter(a => a !== audioURL);
this.setState({audios});
}
render() {
const {recording, audios} = this.state;
return (
<div className="camera">
<audio
style={{width: 400}}
ref={a => {
this.audio = a;
}}>
<p>Audio stream not available. </p>
</audio>
<div>
{!recording && <button onClick={e => this.startRecording(e)}>Record</button>}
{recording && <button onClick={e => this.stopRecording(e)}>Stop</button>}
</div>
<div>
<h3>Recorded audios:</h3>
{audios.map((audioURL, i) => (
<div key={`audio_${i}`}>
<audio controls style={{width: 200}} src={audioURL} />
<div>
<button onClick={() => this.deleteAudio(audioURL)}>Delete</button>
</div>
</div>
))}
</div>
</div>
);
}
}
export default RecordingAPI
如果有人有另一种使用react-native-web进行录制并通过fetch发送的方式,请告诉我