Question

我正在制作通讯录，但遇到了问题。告诉我，str和list有问题。我是python的新手，所以我真的不知道该怎么做。这是完整的程序：

print("\n This is your address book.")

import os
import time

saveFile = open("ContactList.txt", "r")
ContactsString = saveFile.read()
saveFile.close()

Contacts = ContactsString.split('\n')

while '' in Contacts:
    Contacts.remove('')

def printContacts():
    index = 1
    for contact in Contacts:
        print("{}: {}".format(index, contact))
        index = index + 1

def addContact():
    print("You have chosen to add a new contact into your address book.")
    name = input("What's the contacts name? ")

    counter = Contacts.count(name)
    if counter == 0:
        address = input("Enter the address of " + name + ': ')
        email = input("Enter the email of " + name + ': ')
        Contacts.append([ name, address, email ])
    else:
        print("The contact already exists in the address book.")
        print("If you desire to change the contacts current information, enter nr 3 in the menu.")

def browseContacts():
    print("You have chosen to view all your contacts with their name, address and email." "\n")    
    for i in range(0, len(Contacts), 3):
        print(Contacts[i], Contacts[i + 1], Contacts[i + 2], '\n')

def searchContacts():
    print("\n You have chosen to search up a specific contact.")
    searchName = input("Enter the name of the contact that you want to search up: ")

    searchFound = False
    for i in range(0, len(Contacts), 3):
        if searchName == Contacts[i]:
            searchName = True
            break

    if searchFound == True:
        print(Contacts[i], Contacts[i + 1], Contacts[i + 2], "\n")
    else:
        print("We couldn't find " + searchName + " in the address book.")
        print("Check whether your spelling was correct or not.")
        time.sleep(4)

def deleteContact():
    print('\n You have chosen option 4, to delete a specific contact from your address book')
    printContacts()
    deletename = input(' Enter the name of the contact you wish to delete from your address book: ').title()

    deletefound = False
    for i in range(0, len(Contacts), 3): #finds the contact the user wants to delete. It only iterates through each third post so that it only goes through the names of the contact.
        if deletename == Contacts[i]:
            deletefound = True
            break

    if deletefound == True:
        Contacts.pop(i) # deletes the contact information from the list
        Contacts.pop(i)
        Contacts.pop(i)
        print('\n ' + deletename + 'has been removed from your address book')
    else:
        print('\n ' + deletename + "doesn't exist in the address book")

def modifyContacts():
    print("You have chosen option 5, to update a specific contact in your address book.")
    printContacts()
    newName = input("Enter the name of the contact you wish to update: ")

    modifyFound = False
    for i in range(0, len(Contacts), 3):
        if newName == Contacts[i]:
            modifyFound = True
            break

    if modifyFound == True:
        Contacts[i]       = input(' Enter the new name of '    + newName            + ': ')
        Contacts[i + 1]   = input(' Enter the new address of ' + Contacts[i] + ': ')
        Contacts[i + 2]   = input(' Enter the new e-mail of '  + Contacts[i] + ': ')
        print('\n The contact has now been updated')
    else:
        print("\n " + newName + " doesn't exist in the address book")
        print(" You can add " + newName + "to your address book by pressing 1 in the menu below")
        time.sleep(4)


running = True
while running == True:

    print('''
===================================================================
 Menu:

 1: Add new contact (press 1)
 2: Show all contacts (press 2)
 3: Show a specific contact (press 3)
 4: Delete contact (press 4)
 5: Update contact (press 5)
 6: Quit program (press 6)

===================================================================''')

    actionchoice = input('\n Please enter your choice of action: ')

    if actionchoice == '1':   
        addContact()

    elif actionchoice == '2':
        browseContacts()

    elif actionchoice == '3':
        searchContacts()

    elif actionchoice == '4':
        deleteContact()

    elif actionchoice == '5':
        modifyContacts()

    elif actionchoice == '6':
        print('\n Shutting down. Thank you for using the adressbook! \n')
        running = False

    else:
        print('\n The entered command does not exist within this program')
        print(' Please enter one of the actions shown in the menu: \n')
        time.sleep(4)


    saveFile = open("ContactList.txt", "w") 
    for x in range(0, len(Contacts), 3):
        saveFile.write("\n" + Contacts[x]     + "\n")
        saveFile.write(       Contacts[x + 1] + "\n")
        saveFile.write(       Contacts[x + 2] + "\n")
    saveFile.close()

问题到最后，问题说：

Exception has occurred: TypeError
**can only concatenate str (not "list") to str**
  File "C:\Users\Anvandare\Documents\Programmering1\Arbetet\addressbook.py", line 162, in <module>
    saveFile.write("\n" + Contacts[x]     + "\n")

换句话说，这就是问题所在

saveFile.write("\n" + Contacts[x]     + "\n")

我应该怎么做才能工作？

Answer 1

此行是错误的：

Contacts.append([ name, address, email ])

这不是将每个变量附加为列表的单独元素，而是在Contacts中创建嵌套列表。应该是：

Contacts.append(name)
Contacts.append(address)
Contacts.append(email)

或：

Concacts += [ name, address, email ]

您还需要修复printContacts()才能像其他代码一样，以3组为一组来处理Contacts。

def printContacts():
    index = 1
    for i in range(0, len(Contacts), 3):
        print("{}: {} {} {}".format(index, *Contacts[i:i+3]))
        index = index + 1

恕我直言，Contacts最好是字典列表，但是这样做将需要重写90％的代码，而我在这里不打算这样做。

地址簿上的str发生错误

1 个答案: