Question

因此，我们的想法是从一个数组中删除其他数组的编号列表，但仅删除第一个数组，解决该问题的任何帮助将不胜感激。

$my_array = array("Sandra Loor,593984076233","Adrian,593998016010","Lucas,593999843424");


function myFilter($string) {
    $to_remove = array("593984076233","593998016010");
    foreach($to_remove as $remove)  {
        return strpos($string, $remove) === false;
    }

}

$newArray = array_filter($my_array, 'myFilter');

foreach ($newArray as $val){
    echo $val.'<br>';
}

Answer 1

问题是您的过滤器将始终从循环的第一次迭代开始return。相反，如果找到该条目，它将返回false，并在循环结束时返回true（即完全找不到）...

function myFilter($string) {
    $to_remove = array("593984076233","593998016010");
    foreach($to_remove as $remove)  {
        if ( strpos($string, $remove) !== false )
            return false;
    }
    return true;
}

Answer 2

另一种方法是使用preg_grep在数组中搜索要删除的项目，然后使用array_diff删除它们。

$my_array = array("Sandra Loor,593984076233","Adrian,593998016010","Lucas,593999843424");
$to_remove = array("593984076233","593998016010");

$to_remove = "/" . implode("|", $to_remove) . "/";
$match = preg_grep($to_remove, $my_array);
$filtered = array_diff($my_array, $match);

var_dump($filtered);
// Lucas,593999843424

https://3v4l.org/PZ4I6

您还可以像这样将其捆扎成一个衬板：

$my_array = array("Sandra Loor,593984076233","Adrian,593998016010","Lucas,593999843424");
$to_remove = array("593984076233","593998016010");

$filtered = array_diff($my_array, preg_grep("/" . implode("|", $to_remove) . "/", $my_array));

var_dump($filtered);

如果数组包含另一个数组中的字符串，则删除

2 个答案: