Question

如您所见，我有一个具有重复订单编号的数组因为一个订单可以有多个库存商品（stockitemname）。如何合并数组，以便汇总总字段，不再重复订购编号，并将所有库存商品名称置于相同的orderId下？

有人能解决这个问题吗？

Array ( [0] => Array 
       ([orderId] => 1544100294 
        [total] => 215.28 
        [receivedate] => 0000-00-00 
        [stockitemname] => "The Gu" red shirt XML tag t-shirt (White) XXS 
        [customerid] => 10 ) 
    [1] => Array 
       ( [orderId] => 1544119651 
        [total] => 37.38 
        [receivedate] => 0000-00-00 
        [stockitemname] => USB rocket launcher (Gray) 
        [customerid] => 10 ) 
    [2] => Array 
        ( [orderId] => 1544100294 
        [total] => 1614.60 
        [receivedate] => 0000-00-00 
        [stockitemname] => Large sized bubblewrap roll 50m 
        [customerid] => 10 ) )

根据查询结果创建数组：

SELECT oc.orderId, SUM(so.quantity*si.RecommendedRetailPrice) total, oc.receivedate, si.stockitemname, ru.customerid
FROM orderbycustomers oc 
JOIN registered_users ru 
ON oc.customerid = ru.customerid 
JOIN stockitemorders so 
ON oc.orderId = so.orderId 
JOIN stockitems si 
ON so.StockItemID = si.StockItemID
WHERE oc.customerid = $customerid
GROUP BY si.stockitemname
ORDER BY oc.receivedate

Answer 1

一种以顺序收集stockitems的方法可能是这样的：

<?php
 $result = [];
 foreach ($ordersFromQuery as $order) {
   $result[$order['orderId']][] = $order;
 }
?>

Answer 2

在stockitems中获得具有相同id的{{1}}的另一种方法。

unique array

Here，您可以看到它正常工作！

在PHP中合并具有重复值的多维数组

2 个答案: