Question

我已经完成了医生管理系统的登录屏幕和菜单。用户登录并发送到主菜单，根据角色类型，他们在每个子菜单上具有不同的控件。

一切正常，现在该进行测试了。

我从未做过自动化测试-单元，集成或端到端。

据我了解，最好将业务逻辑与表示逻辑分开，并且仅对业务逻辑进行单元测试？

请记住，按钮可见性和消息框是演示逻辑，对吗？并且最适合用于验证功能的手动测试计划？是吗？

我确定我应该对登录是否成功进行单元测试？但是，该方法不依赖数据库吗？那是集成测试吗？

这是我的代码

登录表单

 private void btnLogin_Click(object sender, EventArgs e)
    {


        //Try and open a connection with database and run the code
        try
        {

            //Create new instance of sql connection, pass in the connection string for BayOneSurgerySystem.mdf to connect to database.
            SqlConnection conn = new SqlConnection(@"Data Source=(LocalDB)\MSSQLLocalDB;AttachDbFilename=C:\Users\davie\Documents\UniWork\Software Engineering\BayOneSurgerySystem1.0\Database\BayOneSystem.mdf;Integrated Security=True;Connect Timeout=30");

            //Create new instance of SQlCommand and pass in a query to be called to retrieve table data for username and passwords aswell as the connection object.
            SqlCommand cmd = new SqlCommand("SELECT * FROM Users WHERE Username = @username and Password = @password", conn);
            //This passes user input into @username and @password
            cmd.Parameters.AddWithValue("@username", txtBoxUsername.Text);
            cmd.Parameters.AddWithValue("@password", txtBoxPassword.Text);

            //Open connection with database
            conn.Open();

            //Create new instance of dataSet to hold the data retrieved from sql query
            DataSet ds = new DataSet();
            //Create new instance of DataAdpater to retrieve the data pass in Sql command
            SqlDataAdapter da = new SqlDataAdapter(cmd);
            //using DataAdapter fill in dataSet wiht data if user input and stored data matches
            da.Fill(ds);

            //Close the connection now data table is filled with username and password
            conn.Close();

            //declare bool, true if there is a match with database and user input
            bool loginSuccess = (ds.Tables[0].Rows.Count == 1);


            //if login success is true then open menu
            if (loginSuccess)
            {
                /*Change state of enum RoleTypes based on result from dataSet Role_ID column.
                 In UserRole table records are as follows: 
                 Role_ID 1 = PracticeManager
                 2 = Doctor
                 3 = Receptionist*/

                //Print role_ID to console to check that is been set.
                Console.WriteLine(ds.Tables[0].Rows[0]["Role_ID"]);

                try
                {
                    //Condition for the switch statement is: check Role_ID from UserRoles table
                    switch (ds.Tables[0].Rows[0]["Role_ID"])
                    {
                        //if the case is that Role_ID for the user logged in is 1 then run the function etc.
                        case 1:
                            {
                                Roles.Role = Roles.RoleType.practiceManager;
                                Console.WriteLine("Role type changed to " + Roles.Role);
                            }
                            break;
                        case 2:
                            {
                                Roles.Role = Roles.RoleType.doctor;
                                Console.WriteLine("Role type changed to " + Roles.Role);
                            }
                            break;
                        case 3:
                            {
                                Roles.Role = Roles.RoleType.receptionist;
                                Console.WriteLine("Role type changed to " + Roles.Role);
                            }
                            break;
                        default:
                            break;

                    }
                }//Switch condition cannot be reached then catch exception and print to console.
                catch (Exception ex)
                {
                    Console.WriteLine(ex);
                }


                Console.WriteLine("Logged in.");
                FrmMenu menu = new FrmMenu();
                menu.Show();
                this.Hide();
            }
            else
            {
                MessageBox.Show("Invalid username or password.", "Error!", MessageBoxButtons.RetryCancel);
                Console.WriteLine("Not logged in");
            }


        }

        //If connection cant be opened diplsay error message and catch exception and print to console
        catch (Exception ex)
        {
            Console.WriteLine(ex);
            MessageBox.Show("Sorry can't connect");
        }



    }

}

}

角色类别

 public static class Roles
{
    /*The RoleType enum is declared here and changed in form login. RoleType is the condition for button visibility
    I.e if roletype is doctor, show doctor buttons*/
    public static RoleType Role;
    public enum RoleType
    {
        practiceManager,
        doctor,
        receptionist

    }


}

患者表格

//if this is clicked, display yesNo messagebox. If yes, logout.
    private void btnLogout_Click(object sender, EventArgs e)
    {
        if (MessageBox.Show("Are you sure?", "Exit", MessageBoxButtons.YesNo, MessageBoxIcon.Question) == DialogResult.Yes)
        {
            FrmLogin logout = new FrmLogin();
            logout.Show();
            this.Close();
        }
    }

    private void FrmPatients_Load(object sender, EventArgs e)
    {

        /*Buttons are visible depending on access level. Permissions are as follows:
         * Practice Manager - Patient Records
           Doctor - Register Patient, Patient notes
           Receptionist - New Patient, Register Patient*/
        if (Roles.Role == Roles.RoleType.practiceManager)
        {
            this.btnNewPatient.Visible = false;
            this.btnNotes.Visible = false;
            this.btnSignIn.Visible = false;

        }

        else if (Roles.Role == Roles.RoleType.doctor)
        {
            this.btnNewPatient.Visible = false;
        }
        else
        {
            this.btnNotes.Visible = false;
        }

    }

    //if this is clicked return to main menu
    private void pcBxBack_Click(object sender, EventArgs e)
    {
        FrmMenu menu = new FrmMenu();
        this.Close();
        menu.Show();
    }
}

}

测试课程

 [TestClass]

     public class LoginTests
     {
       [TestMethod]
         public void Constuctor_NormalData_Login_Is_Successful()
         {

            //Arrange
            //Act
            //Assert
          }


        [TestMethod]
        public void Constructor_RoleTypeEnum_RoleType_Changes()
        {
           //Arrange
           //Act
           //Assert

         }


       }

您对自动测试的用途有何建议？

我有一个手动表，其中包含21个测试，用于验证所有消息框，按钮单击事件和按钮可见性。

对于A，我确实需要一些自动化测试。如您所见，我已经具有用于测试角色类型枚举和成功登录的模板，这是我可以看到的仅有的两种显而易见的测试方法。

谢谢！

Answer 1

在这种情况下，请避免进行单元测试，而要进行端到端测试。

您的问题非常模糊-在堆栈溢出时我们尝试避免这种情况，因为它很难回答。最好的答案将是模糊的。在最坏的情况下，问题将被投票决定结束，而提问者（即您）将失去精力。

话虽如此，我却想去一个模糊的答案。

看看您的btnLogin_Click方法，我发现您尚未将业务逻辑与用户界面分开。所述方法知道如何连接到数据库以及如何本地查询数据库，并且知道要更新数据库的用户界面，还知道如何登录到控制台。它可能知道更多，但这足以让我向您建议不要进行单元测试。
简而言之，单元测试是一种验证机器外观和性能的齿轮的方法。
您的机器上有Alla嵌齿轮和杠杆以及冲刺和主轴。我并不是说您的代码很糟糕；但是如果您要单元测试，那么您将很难过。

改为进行端到端测试。
Visual Studio有一种方法可以automate applications。（在解释Visual Studio的功能时，我不知道您是否必须具有特殊的许可证级别，因为Microsoft会“忘记”来描述这一点。
然后是Sikuli。
还有更多。
我不建议上面的那些或其他任何东西，但这必须由您选择。挖掘并测试找到您喜欢的人。许多是F / OSS。

HTH
和快乐的黑客入侵！

您如何知道是自动化测试还是使用手册？

1 个答案: